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lasttccasey
 2 years ago
Best ResponseYou've already chosen the best response.0This is a straight line? Cleans up to be\[y=17x+10\]

SugarRainbow
 2 years ago
Best ResponseYou've already chosen the best response.0no like your supposed to get two different x's and then plug them in or something so that you can get the asymptote and the vertex

lasttccasey
 2 years ago
Best ResponseYou've already chosen the best response.0Straight lines don't have vertexes or asymptotes. Make sure you wrote the equation correctly. There should at least be an x^2 somewhere.

SugarRainbow
 2 years ago
Best ResponseYou've already chosen the best response.0oh yeah oops its 1016xx^2=0

SugarRainbow
 2 years ago
Best ResponseYou've already chosen the best response.0well i have to go maybe you can help me later so bye ^^

lasttccasey
 2 years ago
Best ResponseYou've already chosen the best response.0Okay cleaning this up into the ax^2+bx+c=0 format we can quickly find the vertex: x^216x+10 Vertex = (h,k) h=b/2a h=(16)/(2*(1)) h=8 Plus h back into the equation for the x values to find the k value: (8)^216(8)+10=k k=74 Thus the vertex is (8,74)

lasttccasey
 2 years ago
Best ResponseYou've already chosen the best response.0And there are no asymptotes for parabolas.
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