anonymous
  • anonymous
10-16x-x=0 please help! i need to find vertex and asymptote
Mathematics
schrodinger
  • schrodinger
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lasttccasey
  • lasttccasey
This is a straight line? Cleans up to be\[y=-17x+10\]
anonymous
  • anonymous
no like your supposed to get two different x's and then plug them in or something so that you can get the asymptote and the vertex
lasttccasey
  • lasttccasey
Straight lines don't have vertexes or asymptotes. Make sure you wrote the equation correctly. There should at least be an x^2 somewhere.

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anonymous
  • anonymous
oh yeah oops its 10-16x-x^2=0
anonymous
  • anonymous
hello?
anonymous
  • anonymous
well i have to go maybe you can help me later so bye ^-^
lasttccasey
  • lasttccasey
Okay cleaning this up into the ax^2+bx+c=0 format we can quickly find the vertex: -x^2-16x+10 Vertex = (h,k) h=-b/2a h=-(-16)/(2*(-1)) h=-8 Plus h back into the equation for the x values to find the k value: -(-8)^2-16(-8)+10=k k=74 Thus the vertex is (-8,74)
lasttccasey
  • lasttccasey
And there are no asymptotes for parabolas.

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