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SugarRainbow Group Title

10-16x-x=0 please help! i need to find vertex and asymptote

  • one year ago
  • one year ago

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  1. lasttccasey Group Title
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    This is a straight line? Cleans up to be\[y=-17x+10\]

    • one year ago
  2. SugarRainbow Group Title
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    no like your supposed to get two different x's and then plug them in or something so that you can get the asymptote and the vertex

    • one year ago
  3. lasttccasey Group Title
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    Straight lines don't have vertexes or asymptotes. Make sure you wrote the equation correctly. There should at least be an x^2 somewhere.

    • one year ago
  4. SugarRainbow Group Title
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    oh yeah oops its 10-16x-x^2=0

    • one year ago
  5. SugarRainbow Group Title
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    hello?

    • one year ago
  6. SugarRainbow Group Title
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    well i have to go maybe you can help me later so bye ^-^

    • one year ago
  7. lasttccasey Group Title
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    Okay cleaning this up into the ax^2+bx+c=0 format we can quickly find the vertex: -x^2-16x+10 Vertex = (h,k) h=-b/2a h=-(-16)/(2*(-1)) h=-8 Plus h back into the equation for the x values to find the k value: -(-8)^2-16(-8)+10=k k=74 Thus the vertex is (-8,74)

    • one year ago
  8. lasttccasey Group Title
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    And there are no asymptotes for parabolas.

    • one year ago
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