A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
1016xx=0 please help! i need to find
vertex and asymptote
anonymous
 3 years ago
1016xx=0 please help! i need to find vertex and asymptote

This Question is Closed

lasttccasey
 3 years ago
Best ResponseYou've already chosen the best response.0This is a straight line? Cleans up to be\[y=17x+10\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no like your supposed to get two different x's and then plug them in or something so that you can get the asymptote and the vertex

lasttccasey
 3 years ago
Best ResponseYou've already chosen the best response.0Straight lines don't have vertexes or asymptotes. Make sure you wrote the equation correctly. There should at least be an x^2 somewhere.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh yeah oops its 1016xx^2=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well i have to go maybe you can help me later so bye ^^

lasttccasey
 3 years ago
Best ResponseYou've already chosen the best response.0Okay cleaning this up into the ax^2+bx+c=0 format we can quickly find the vertex: x^216x+10 Vertex = (h,k) h=b/2a h=(16)/(2*(1)) h=8 Plus h back into the equation for the x values to find the k value: (8)^216(8)+10=k k=74 Thus the vertex is (8,74)

lasttccasey
 3 years ago
Best ResponseYou've already chosen the best response.0And there are no asymptotes for parabolas.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.