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10-16x-x=0 please help! i need to find vertex and asymptote

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This is a straight line? Cleans up to be\[y=-17x+10\]
no like your supposed to get two different x's and then plug them in or something so that you can get the asymptote and the vertex
Straight lines don't have vertexes or asymptotes. Make sure you wrote the equation correctly. There should at least be an x^2 somewhere.

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oh yeah oops its 10-16x-x^2=0
well i have to go maybe you can help me later so bye ^-^
Okay cleaning this up into the ax^2+bx+c=0 format we can quickly find the vertex: -x^2-16x+10 Vertex = (h,k) h=-b/2a h=-(-16)/(2*(-1)) h=-8 Plus h back into the equation for the x values to find the k value: -(-8)^2-16(-8)+10=k k=74 Thus the vertex is (-8,74)
And there are no asymptotes for parabolas.

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