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A student scored 78 and 95 on his first two quizzes. Use a compound inequality to find the possible values for a third quiz score that would give him an average between 80 and 90, inclusive. (1 point)
67 ≤ x ≤ 97
78 ≤ x ≤ 95
80 ≤ x ≤ 90
86 ≤ x ≤ 87
Would it be B???
now it would not
first of all you are given that he gets an average between 80 and 90
so you know it is between these two values
you dont know his exact average so it could be 80 or higher but it must be 90 or belowe
so it can be equal to 80 or above
and it can be equal to 90 or below
this gives two inequalities
80 ≤ x
x ≤ 90
this can be written as 1 inequality
80 ≤ x ≤ 90
≤ this means less than or equal to
the one that points the opposite way would be greater than or equal to
think of it as a number line
pointing right is positive meaning the numbers get bigger, getting greater
pointing left is getting smaller so it gets less and less
remember it is called greater than or equal to
less than or equal to because of the line underneath the sign
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can you help with another one???
x – 1 over 5 = 3
x = –14/5 and x = 16/5
x = 14/5 and x = –16/5
x = –14/5 and x = –16/5
x = 14/5 and x = 16/5
okay absolute values
okay so you should sketch a graph
if you do not know how
first you must know
so you know you always get a positive number from whatever is in the | |
so from this you know the graph will show only positive values
so first you will draw the graph of y=x-(1/5)
then you will reflect the negative part of the graph for example
if i have
i will draw the graphs for y=x-2
this would give
now i must draw y=|x-2| well since it is reflected i will have all of the negative part of the graph y=x-2 on the positive side of the graph so it will be like...
I labelled it -(x-2) because the graph y=|x-2| is essentially y=x-2 and the other part is that multiplied by -1
which gives y=-(x-2)
now that we have drawn a graph you know it crosses with each other 2 times so you will make them equal to each other for example
y=x-2 crosses y=4
so make them equal to each other
re arrange to get x
now i know that -(x-2) crosses with 4 so i make them equal
i re arrange to get x
sorry i made a mistake in the graph drawing it should be y=4 not y=3
okay now follow the same thing with your question