At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

i think it is a geometric sequence, just not sure where the ending term is

i think after 12 years you have
\[Pr+Pr^2+Pr^3+...+Pr^{12}\] with \(P=1200\) and \(r=1.05\)

we can write this as
\[Pr(1+r+r^2+r^3+...+r^{11})=Pr\left(\frac{r^{12}-1}{r-1}\right)\]

or even
\[P\left(\frac{r^{13}-r}{r-1}\right)\]

so try
\[1200\left(\frac{(1.05)^{13}-1.05}{.05}\right)\]

ok, was trying it in the calculator

oh damn i was off by an exponent
thought i might have been

Well that wasnt too hard. Had no clue how to set it up. Thank you very much for replying

try this
\[1200\left(\frac{(1.05)^{12}-1}{.05}\right)\]

copy and past into your browser and you will see that it is the same

I will work out the problem with that formula. Makes sense when you see it like this

Thank you again for your help :)