Lukecrayonz
  • Lukecrayonz
sin^2(x-1)/cos(-x)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Lukecrayonz
  • Lukecrayonz
@amistre64
amistre64
  • amistre64
might need to know alittle more about the question
Lukecrayonz
  • Lukecrayonz
It just says to simplify @amistre64

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
already seems "simple" to me :/
amistre64
  • amistre64
you can try to shuffle some things about i spose; sin^2 = 1-cos^2 cos(a+b) = cosa cosb - sina sinb and stuff
amistre64
  • amistre64
cos(-x) = cos(x) ... just some basic trig identities and properties that might be useful
Lukecrayonz
  • Lukecrayonz
@amistre64 would you like the possible answers?
Lukecrayonz
  • Lukecrayonz
Also quick question on another problem I'm stuck on.
amistre64
  • amistre64
options would be able to narrow it down :)
Lukecrayonz
  • Lukecrayonz
@amistre64 You there?
Lukecrayonz
  • Lukecrayonz
@saifoo.khan
Lukecrayonz
  • Lukecrayonz
A. -sinx B. cosx C. Sinx D. -cosx
saifoo.khan
  • saifoo.khan
Where are you stuck? @Lukecrayonz
Lukecrayonz
  • Lukecrayonz
@saifoo.khan don't even know where to start :'(((
saifoo.khan
  • saifoo.khan
Use the 4th identity for numerator. http://www.a-levelmathstutor.com/images/trigonometry/ca-identities01.jpg
Lukecrayonz
  • Lukecrayonz
The one Sin(A-B)?
saifoo.khan
  • saifoo.khan
Yep.
Lukecrayonz
  • Lukecrayonz
How.. That makes no sense to me?
Lukecrayonz
  • Lukecrayonz
If its sin^2 how would I use Sin(A-B)?
saifoo.khan
  • saifoo.khan
Ohhh. :o
Lukecrayonz
  • Lukecrayonz
hmm?
Lukecrayonz
  • Lukecrayonz
I think I got it
saifoo.khan
  • saifoo.khan
I guess, @satellite73 or @amistre64 will help you here. :/
Lukecrayonz
  • Lukecrayonz
sin^2x-1=-cos^2x cos(-x)=cosx so the answer is -cosx
saifoo.khan
  • saifoo.khan
Wait. How?
Lukecrayonz
  • Lukecrayonz
-cos^2x/cosx=-cosx?
saifoo.khan
  • saifoo.khan
Step 1.
Lukecrayonz
  • Lukecrayonz
cos(-x)=cosx
Lukecrayonz
  • Lukecrayonz
Pythagorean identities sin^2x+cos^2x=1
saifoo.khan
  • saifoo.khan
\[\frac{-\cos^2(x-1) +1}{\cos(-x)}\]Then we should get this?
amistre64
  • amistre64
shuffling trigs is a pain :)
saifoo.khan
  • saifoo.khan
No pain, no gain. ;)
amistre64
  • amistre64
do you need to show work?
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=simplify+sin%5E2%28x-1%29%2Fcos%28-x%29+ i dont see it popping out an option that you have

Looking for something else?

Not the answer you are looking for? Search for more explanations.