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Lukecrayonz

  • 3 years ago

sin^2(x-1)/cos(-x)

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  1. Lukecrayonz
    • 3 years ago
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    @amistre64

  2. amistre64
    • 3 years ago
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    might need to know alittle more about the question

  3. Lukecrayonz
    • 3 years ago
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    It just says to simplify @amistre64

  4. amistre64
    • 3 years ago
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    already seems "simple" to me :/

  5. amistre64
    • 3 years ago
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    you can try to shuffle some things about i spose; sin^2 = 1-cos^2 cos(a+b) = cosa cosb - sina sinb and stuff

  6. amistre64
    • 3 years ago
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    cos(-x) = cos(x) ... just some basic trig identities and properties that might be useful

  7. Lukecrayonz
    • 3 years ago
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    @amistre64 would you like the possible answers?

  8. Lukecrayonz
    • 3 years ago
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    Also quick question on another problem I'm stuck on.

  9. amistre64
    • 3 years ago
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    options would be able to narrow it down :)

  10. Lukecrayonz
    • 3 years ago
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    @amistre64 You there?

  11. Lukecrayonz
    • 3 years ago
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    @saifoo.khan

  12. Lukecrayonz
    • 3 years ago
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    A. -sinx B. cosx C. Sinx D. -cosx

  13. saifoo.khan
    • 3 years ago
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    Where are you stuck? @Lukecrayonz

  14. Lukecrayonz
    • 3 years ago
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    @saifoo.khan don't even know where to start :'(((

  15. saifoo.khan
    • 3 years ago
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    Use the 4th identity for numerator. http://www.a-levelmathstutor.com/images/trigonometry/ca-identities01.jpg

  16. Lukecrayonz
    • 3 years ago
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    The one Sin(A-B)?

  17. saifoo.khan
    • 3 years ago
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    Yep.

  18. Lukecrayonz
    • 3 years ago
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    How.. That makes no sense to me?

  19. Lukecrayonz
    • 3 years ago
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    If its sin^2 how would I use Sin(A-B)?

  20. saifoo.khan
    • 3 years ago
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    Ohhh. :o

  21. Lukecrayonz
    • 3 years ago
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    hmm?

  22. Lukecrayonz
    • 3 years ago
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    I think I got it

  23. saifoo.khan
    • 3 years ago
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    I guess, @satellite73 or @amistre64 will help you here. :/

  24. Lukecrayonz
    • 3 years ago
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    sin^2x-1=-cos^2x cos(-x)=cosx so the answer is -cosx

  25. saifoo.khan
    • 3 years ago
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    Wait. How?

  26. Lukecrayonz
    • 3 years ago
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    -cos^2x/cosx=-cosx?

  27. saifoo.khan
    • 3 years ago
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    Step 1.

  28. Lukecrayonz
    • 3 years ago
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    cos(-x)=cosx

  29. Lukecrayonz
    • 3 years ago
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    Pythagorean identities sin^2x+cos^2x=1

  30. saifoo.khan
    • 3 years ago
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    \[\frac{-\cos^2(x-1) +1}{\cos(-x)}\]Then we should get this?

  31. amistre64
    • 3 years ago
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    shuffling trigs is a pain :)

  32. saifoo.khan
    • 3 years ago
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    No pain, no gain. ;)

  33. amistre64
    • 3 years ago
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    do you need to show work?

  34. amistre64
    • 3 years ago
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    http://www.wolframalpha.com/input/?i=simplify+sin%5E2%28x-1%29%2Fcos%28-x%29+ i dont see it popping out an option that you have

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