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might need to know alittle more about the question
It just says to simplify @amistre64

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Other answers:

already seems "simple" to me :/
you can try to shuffle some things about i spose; sin^2 = 1-cos^2 cos(a+b) = cosa cosb - sina sinb and stuff
cos(-x) = cos(x) ... just some basic trig identities and properties that might be useful
@amistre64 would you like the possible answers?
Also quick question on another problem I'm stuck on.
options would be able to narrow it down :)
@amistre64 You there?
@saifoo.khan
A. -sinx B. cosx C. Sinx D. -cosx
Where are you stuck? @Lukecrayonz
@saifoo.khan don't even know where to start :'(((
Use the 4th identity for numerator. http://www.a-levelmathstutor.com/images/trigonometry/ca-identities01.jpg
The one Sin(A-B)?
Yep.
How.. That makes no sense to me?
If its sin^2 how would I use Sin(A-B)?
Ohhh. :o
hmm?
I think I got it
I guess, @satellite73 or @amistre64 will help you here. :/
sin^2x-1=-cos^2x cos(-x)=cosx so the answer is -cosx
Wait. How?
-cos^2x/cosx=-cosx?
Step 1.
cos(-x)=cosx
Pythagorean identities sin^2x+cos^2x=1
\[\frac{-\cos^2(x-1) +1}{\cos(-x)}\]Then we should get this?
shuffling trigs is a pain :)
No pain, no gain. ;)
do you need to show work?
http://www.wolframalpha.com/input/?i=simplify+sin%5E2%28x-1%29%2Fcos%28-x%29+ i dont see it popping out an option that you have

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