sin^2(x-1)/cos(-x)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

might need to know alittle more about the question
It just says to simplify @amistre64

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

already seems "simple" to me :/
you can try to shuffle some things about i spose; sin^2 = 1-cos^2 cos(a+b) = cosa cosb - sina sinb and stuff
cos(-x) = cos(x) ... just some basic trig identities and properties that might be useful
@amistre64 would you like the possible answers?
Also quick question on another problem I'm stuck on.
options would be able to narrow it down :)
@amistre64 You there?
@saifoo.khan
A. -sinx B. cosx C. Sinx D. -cosx
Where are you stuck? @Lukecrayonz
@saifoo.khan don't even know where to start :'(((
Use the 4th identity for numerator. http://www.a-levelmathstutor.com/images/trigonometry/ca-identities01.jpg
The one Sin(A-B)?
Yep.
How.. That makes no sense to me?
If its sin^2 how would I use Sin(A-B)?
Ohhh. :o
hmm?
I think I got it
I guess, @satellite73 or @amistre64 will help you here. :/
sin^2x-1=-cos^2x cos(-x)=cosx so the answer is -cosx
Wait. How?
-cos^2x/cosx=-cosx?
Step 1.
cos(-x)=cosx
Pythagorean identities sin^2x+cos^2x=1
\[\frac{-\cos^2(x-1) +1}{\cos(-x)}\]Then we should get this?
shuffling trigs is a pain :)
No pain, no gain. ;)
do you need to show work?
http://www.wolframalpha.com/input/?i=simplify+sin%5E2%28x-1%29%2Fcos%28-x%29+ i dont see it popping out an option that you have

Not the answer you are looking for?

Search for more explanations.

Ask your own question