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ashley4328
Group Title
Find the value of k so that the line passing through the given points has slope m. Write an equation of the line in pointslope form.
(k, 4k), (k+2,3k), m = 1
 one year ago
 one year ago
ashley4328 Group Title
Find the value of k so that the line passing through the given points has slope m. Write an equation of the line in pointslope form. (k, 4k), (k+2,3k), m = 1
 one year ago
 one year ago

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mark_o. Group TitleBest ResponseYou've already chosen the best response.1
given (k, 4k), (k+2,3k), m = 1 m=(4k3k)/(k(k+2)) m=1k/(2)=1 continue here and find k=? now using the point (k, 4k)=(?,?) using the value of k, and using m=1 set up an Equation using the formula y  y1= m (x  x1) y  ? = 1 (x  ?) then simplify this to make point slope form
 one year ago

ashley4328 Group TitleBest ResponseYou've already chosen the best response.0
Would it be y+2 = 1/2 (x  .5) ?
 one year ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
using the points and slope given (k, 4k), (k+2,3k), m = 1 (4k3k) m=  (k(k+2)) 1k m =  = 1 2 therefore k=2 now the points are (k, 4k)=(2,8) why? (k+2,3k)=(4,6) why? now using either of these points (2,8) or (4,6) and using the formula of pointslope form. y  y1= m( x  x1) y  8 = 1(x  2 ) yes or no?
 one year ago

ashley4328 Group TitleBest ResponseYou've already chosen the best response.0
Because k=2 and it's just k in the first x and 4 times 2 is 8 so it's (2,8) and 2+2 = 4 and 3 times 2 = 6 so it's (4,6). Yes that's correct! Thank you! I just wasn't sure how you would find it. I kept getting 1 over 2. I just couldn't figure out what to do with it.
 one year ago
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