anonymous
  • anonymous
Solve x2 + 4x + 8 = 0
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
You have to use the quadratic equation, do you know it?
anonymous
  • anonymous
no
anonymous
  • anonymous
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

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anonymous
  • anonymous
ax2+bx+c=0 Formula: (-b+-sqrt(b squared -4*a*c))/2a
anonymous
  • anonymous
so?
anonymous
  • anonymous
a=1, b=4, c=8, plug 'em in
anonymous
  • anonymous
x equals negative 2 plus or minus 4 I?
anonymous
  • anonymous
BluFoot?
anonymous
  • anonymous
+- stands for two possible resoults, both are correct
anonymous
  • anonymous
\[ax^2 + bx + c = 0\]\[x^2 + 4x + 8 = 0\]a = 1 b = 4 c = 8 \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a } \] As BluFoot mentioned, just plug them in.\[x=\frac{ -(4) \pm \sqrt{(4)^2-4(1)(8)} }{ 2(1) } \]
anonymous
  • anonymous
Now lets simplify that a bit. \[x=\frac{ -(4) \pm \sqrt{(4)^2-4(1)(8)} }{ 2(1)} \] \[x=\frac{ -(4) \pm \sqrt{16-32} }{ 2 }\]
anonymous
  • anonymous
x equals negative 4 plus or minus 4 I?
anonymous
  • anonymous
jazy?

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