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BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.1You have to use the quadratic equation, do you know it?

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.1\[x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }\]

nickersia
 2 years ago
Best ResponseYou've already chosen the best response.0ax2+bx+c=0 Formula: (b+sqrt(b squared 4*a*c))/2a

BluFoot
 2 years ago
Best ResponseYou've already chosen the best response.1a=1, b=4, c=8, plug 'em in

daze
 2 years ago
Best ResponseYou've already chosen the best response.0x equals negative 2 plus or minus 4 I?

nickersia
 2 years ago
Best ResponseYou've already chosen the best response.0+ stands for two possible resoults, both are correct

jazy
 2 years ago
Best ResponseYou've already chosen the best response.0\[ax^2 + bx + c = 0\]\[x^2 + 4x + 8 = 0\]a = 1 b = 4 c = 8 \[x=\frac{ b \pm \sqrt{b^24ac} }{ 2a } \] As BluFoot mentioned, just plug them in.\[x=\frac{ (4) \pm \sqrt{(4)^24(1)(8)} }{ 2(1) } \]

jazy
 2 years ago
Best ResponseYou've already chosen the best response.0Now lets simplify that a bit. \[x=\frac{ (4) \pm \sqrt{(4)^24(1)(8)} }{ 2(1)} \] \[x=\frac{ (4) \pm \sqrt{1632} }{ 2 }\]

daze
 2 years ago
Best ResponseYou've already chosen the best response.0x equals negative 4 plus or minus 4 I?
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