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BluFoot Group TitleBest ResponseYou've already chosen the best response.1
You have to use the quadratic equation, do you know it?
 one year ago

BluFoot Group TitleBest ResponseYou've already chosen the best response.1
\[x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }\]
 one year ago

nickersia Group TitleBest ResponseYou've already chosen the best response.0
ax2+bx+c=0 Formula: (b+sqrt(b squared 4*a*c))/2a
 one year ago

BluFoot Group TitleBest ResponseYou've already chosen the best response.1
a=1, b=4, c=8, plug 'em in
 one year ago

daze Group TitleBest ResponseYou've already chosen the best response.0
x equals negative 2 plus or minus 4 I?
 one year ago

nickersia Group TitleBest ResponseYou've already chosen the best response.0
+ stands for two possible resoults, both are correct
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
\[ax^2 + bx + c = 0\]\[x^2 + 4x + 8 = 0\]a = 1 b = 4 c = 8 \[x=\frac{ b \pm \sqrt{b^24ac} }{ 2a } \] As BluFoot mentioned, just plug them in.\[x=\frac{ (4) \pm \sqrt{(4)^24(1)(8)} }{ 2(1) } \]
 one year ago

jazy Group TitleBest ResponseYou've already chosen the best response.0
Now lets simplify that a bit. \[x=\frac{ (4) \pm \sqrt{(4)^24(1)(8)} }{ 2(1)} \] \[x=\frac{ (4) \pm \sqrt{1632} }{ 2 }\]
 one year ago

daze Group TitleBest ResponseYou've already chosen the best response.0
x equals negative 4 plus or minus 4 I?
 one year ago
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