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BluFootBest ResponseYou've already chosen the best response.1
You have to use the quadratic equation, do you know it?
 one year ago

BluFootBest ResponseYou've already chosen the best response.1
\[x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }\]
 one year ago

nickersiaBest ResponseYou've already chosen the best response.0
ax2+bx+c=0 Formula: (b+sqrt(b squared 4*a*c))/2a
 one year ago

BluFootBest ResponseYou've already chosen the best response.1
a=1, b=4, c=8, plug 'em in
 one year ago

dazeBest ResponseYou've already chosen the best response.0
x equals negative 2 plus or minus 4 I?
 one year ago

nickersiaBest ResponseYou've already chosen the best response.0
+ stands for two possible resoults, both are correct
 one year ago

jazyBest ResponseYou've already chosen the best response.0
\[ax^2 + bx + c = 0\]\[x^2 + 4x + 8 = 0\]a = 1 b = 4 c = 8 \[x=\frac{ b \pm \sqrt{b^24ac} }{ 2a } \] As BluFoot mentioned, just plug them in.\[x=\frac{ (4) \pm \sqrt{(4)^24(1)(8)} }{ 2(1) } \]
 one year ago

jazyBest ResponseYou've already chosen the best response.0
Now lets simplify that a bit. \[x=\frac{ (4) \pm \sqrt{(4)^24(1)(8)} }{ 2(1)} \] \[x=\frac{ (4) \pm \sqrt{1632} }{ 2 }\]
 one year ago

dazeBest ResponseYou've already chosen the best response.0
x equals negative 4 plus or minus 4 I?
 one year ago
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