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yashar806

  • 2 years ago

3^2x derivative

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  1. edpinho
    • 2 years ago
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    2.3^(2x) ln3

  2. yashar806
    • 2 years ago
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    is it 2.3 ?

  3. edpinho
    • 2 years ago
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    \[2(3^{2x}) \ln 3\]

  4. yashar806
    • 2 years ago
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    ok got it

  5. edpinho
    • 2 years ago
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    need details?

  6. yashar806
    • 2 years ago
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    actually yes

  7. edpinho
    • 2 years ago
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    ok then, so that type of derivetive is a^(u(x)) where "a" is a constant and "u(x)" is the equation, derived i looks like" u(x)' a^(u(x)) ln a", it looks complicated i know :P

  8. yashar806
    • 2 years ago
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    got it ` thank you

  9. edpinho
    • 2 years ago
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    oh and you have to finish by multipling 2 by 3 so final answer is \[6^{2x}\ln 3\]

  10. yashar806
    • 2 years ago
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    use the squeeze theorem to show that if 0le f(x) le 5 , for all x in [ 0 , 1], then lim_{x rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0

  11. yashar806
    • 2 years ago
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    0le f(x) le 5

  12. yashar806
    • 2 years ago
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    \[use the squeeze theorem \to show that if 0\le f(x) \le 5 , for all x \in [ 0 , 1], then \lim_{x \rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0\]

  13. yashar806
    • 2 years ago
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    0le f(x) le 5 , for all x in [ 0 , 1],

  14. edpinho
    • 2 years ago
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    sorry but i cant help you, i've never used the theorem before

  15. edpinho
    • 2 years ago
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    does it say what f(x) is ?

  16. yashar806
    • 2 years ago
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    no

  17. yashar806
    • 2 years ago
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    lim_{x rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0

  18. yashar806
    • 2 years ago
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    \[\lim_{x \rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0 \]

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