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anonymous
 4 years ago
3^2x derivative
anonymous
 4 years ago
3^2x derivative

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok then, so that type of derivetive is a^(u(x)) where "a" is a constant and "u(x)" is the equation, derived i looks like" u(x)' a^(u(x)) ln a", it looks complicated i know :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh and you have to finish by multipling 2 by 3 so final answer is \[6^{2x}\ln 3\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use the squeeze theorem to show that if 0le f(x) le 5 , for all x in [ 0 , 1], then lim_{x rightarrow 0^+} \ \left( e^{x}  1\right) f(x) =0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[use the squeeze theorem \to show that if 0\le f(x) \le 5 , for all x \in [ 0 , 1], then \lim_{x \rightarrow 0^+} \ \left( e^{x}  1\right) f(x) =0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.00le f(x) le 5 , for all x in [ 0 , 1],

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry but i cant help you, i've never used the theorem before

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0does it say what f(x) is ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lim_{x rightarrow 0^+} \ \left( e^{x}  1\right) f(x) =0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0^+} \ \left( e^{x}  1\right) f(x) =0 \]
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