3^2x derivative

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3^2x derivative

Mathematics
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2.3^(2x) ln3
is it 2.3 ?
\[2(3^{2x}) \ln 3\]

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ok got it
need details?
actually yes
ok then, so that type of derivetive is a^(u(x)) where "a" is a constant and "u(x)" is the equation, derived i looks like" u(x)' a^(u(x)) ln a", it looks complicated i know :P
got it ` thank you
oh and you have to finish by multipling 2 by 3 so final answer is \[6^{2x}\ln 3\]
use the squeeze theorem to show that if 0le f(x) le 5 , for all x in [ 0 , 1], then lim_{x rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0
0le f(x) le 5
\[use the squeeze theorem \to show that if 0\le f(x) \le 5 , for all x \in [ 0 , 1], then \lim_{x \rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0\]
0le f(x) le 5 , for all x in [ 0 , 1],
sorry but i cant help you, i've never used the theorem before
does it say what f(x) is ?
no
lim_{x rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0
\[\lim_{x \rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0 \]

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