yashar806
3^2x derivative
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edpinho
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2.3^(2x) ln3
yashar806
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is it 2.3 ?
edpinho
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\[2(3^{2x}) \ln 3\]
yashar806
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ok got it
edpinho
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need details?
yashar806
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actually yes
edpinho
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ok then, so that type of derivetive is a^(u(x)) where "a" is a constant and "u(x)" is the equation, derived i looks like" u(x)' a^(u(x)) ln a", it looks complicated i know :P
yashar806
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got it ` thank you
edpinho
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oh and you have to finish by multipling 2 by 3 so final answer is \[6^{2x}\ln 3\]
yashar806
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use the squeeze theorem to show that if 0le f(x) le 5 , for all x in [ 0 , 1], then lim_{x rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0
yashar806
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0le f(x) le 5
yashar806
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\[use the squeeze theorem \to show that if 0\le f(x) \le 5 , for all x \in [ 0 , 1], then \lim_{x \rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0\]
yashar806
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0le f(x) le 5 , for all x in [ 0 , 1],
edpinho
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sorry but i cant help you, i've never used the theorem before
edpinho
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does it say what f(x) is ?
yashar806
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no
yashar806
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lim_{x rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0
yashar806
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\[\lim_{x \rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0 \]