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cdawg111 Group Title

how do you find the center and the radius of a cirlce..with (x+3)^2+y^2=16

  • one year ago
  • one year ago

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  1. ktnguyen Group Title
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    |dw:1354663805261:dw|

    • one year ago
  2. cdawg111 Group Title
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    so r would be 4?

    • one year ago
  3. cwrw238 Group Title
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    right

    • one year ago
  4. cdawg111 Group Title
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    how do i get the center

    • one year ago
  5. cwrw238 Group Title
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    compare x + 3 with x - h (h is x coordinate of the center) what does that make x cood of centrer?

    • one year ago
  6. cwrw238 Group Title
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    do u follow me?

    • one year ago
  7. cdawg111 Group Title
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    no because i dont have a center

    • one year ago
  8. cwrw238 Group Title
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    center is h comparing the 2 brackets -h = 3 so what does that make h?

    • one year ago
  9. cdawg111 Group Title
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    -3

    • one year ago
  10. cwrw238 Group Title
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    right now in the case of y coordinate we have y^2 so the y cordinate is 0 so center is (-3, 0)

    • one year ago
  11. cdawg111 Group Title
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    and radius is 4 correct

    • one year ago
  12. cwrw238 Group Title
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    yea

    • one year ago
  13. cdawg111 Group Title
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    thanks i got it

    • one year ago
  14. cwrw238 Group Title
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    yw

    • one year ago
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