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Solve x + 3y = 7 if x and y must be whole numbers.
{(0, 5), (1, 3), (2, 1)}
{(2, 1), (1, 4), (0, 7)}
{(1, 2), (4, 1), (7, 0)}
{(0, 5), (1, 4), (2, 1)}
 one year ago
 one year ago
Solve x + 3y = 7 if x and y must be whole numbers. {(0, 5), (1, 3), (2, 1)} {(2, 1), (1, 4), (0, 7)} {(1, 2), (4, 1), (7, 0)} {(0, 5), (1, 4), (2, 1)}
 one year ago
 one year ago

This Question is Closed

LoujoelouBest ResponseYou've already chosen the best response.1
You can plug in the values in and see which of them is correct. A coordinate is (x,y), so you can put the coordinates into the equation and see which set is correct. If you start with the first one: We'll put in (0,5): 0+3(5)=7 15=7 is not true so A can't be the answer. Next we'll go to B and use (2,1): 2+3(1)=7 5=7 is not true so B can't be the answer. Now we'll go to C and use (1,2): 1+3(2)=7 7=7 this is correct so we'll use the second pair of coordinates in C, (4,1): 4+3(1)=7 7=7 This is correct so we'll now use the last pair in the set (7,0): 7+3(0)=7 7=7 Since all three of the coordinate pairs worked in C, C would be your answer :)
 one year ago
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