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eli123 Group Title

the difference of two numbers is 1 and the sum of their squares is 41, find the numbers

  • 2 years ago
  • 2 years ago

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  1. chaguanas Group Title
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    You have to translate the words into math symbols.

    • 2 years ago
  2. eli123 Group Title
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    ok i know that x-x=1

    • 2 years ago
  3. eli123 Group Title
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    and the exponents have to give me 41

    • 2 years ago
  4. chaguanas Group Title
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    For your first response, it would be better if you use a different variable for each number rather than x and x.

    • 2 years ago
  5. eli123 Group Title
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    x-y=1

    • 2 years ago
  6. chaguanas Group Title
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    You are pretty good at this. You need to do the same thing for the second part.

    • 2 years ago
  7. eli123 Group Title
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    ok but

    • 2 years ago
  8. chaguanas Group Title
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    Yah

    • 2 years ago
  9. eli123 Group Title
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    what would the answer be

    • 2 years ago
  10. tamtoan Group Title
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    if your variables are x and y, how do you write the sum of their square ?

    • 2 years ago
  11. eli123 Group Title
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    aaahh i dont know

    • 2 years ago
  12. eli123 Group Title
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    (5,4)?

    • 2 years ago
  13. tamtoan Group Title
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    if the variable is x, the square of that variable is \[x^{2}\] likewise with the other variable ...and the sum of both is ? ...try to write that expression

    • 2 years ago
  14. eli123 Group Title
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    x^2-y^2=1

    • 2 years ago
  15. eli123 Group Title
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    2+2?

    • 2 years ago
  16. eli123 Group Title
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    no no

    • 2 years ago
  17. tamtoan Group Title
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    the sum, not the difference ...and the sum of them is 41..do that again ?

    • 2 years ago
  18. eli123 Group Title
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    4 and 5

    • 2 years ago
  19. tamtoan Group Title
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    where do you get 4 and 5 ?

    • 2 years ago
  20. eli123 Group Title
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    five minus four is 1 and 4^2+5^2 is 41

    • 2 years ago
  21. tamtoan Group Title
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    that's guessing, you guess right, but it's not the way to solve :) you have to write a system of 2 equations and try to solve it.

    • 2 years ago
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