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eli123

  • 3 years ago

the difference of two numbers is 1 and the sum of their squares is 41, find the numbers

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  1. chaguanas
    • 3 years ago
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    You have to translate the words into math symbols.

  2. eli123
    • 3 years ago
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    ok i know that x-x=1

  3. eli123
    • 3 years ago
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    and the exponents have to give me 41

  4. chaguanas
    • 3 years ago
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    For your first response, it would be better if you use a different variable for each number rather than x and x.

  5. eli123
    • 3 years ago
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    x-y=1

  6. chaguanas
    • 3 years ago
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    You are pretty good at this. You need to do the same thing for the second part.

  7. eli123
    • 3 years ago
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    ok but

  8. chaguanas
    • 3 years ago
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    Yah

  9. eli123
    • 3 years ago
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    what would the answer be

  10. tamtoan
    • 3 years ago
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    if your variables are x and y, how do you write the sum of their square ?

  11. eli123
    • 3 years ago
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    aaahh i dont know

  12. eli123
    • 3 years ago
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    (5,4)?

  13. tamtoan
    • 3 years ago
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    if the variable is x, the square of that variable is \[x^{2}\] likewise with the other variable ...and the sum of both is ? ...try to write that expression

  14. eli123
    • 3 years ago
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    x^2-y^2=1

  15. eli123
    • 3 years ago
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    2+2?

  16. eli123
    • 3 years ago
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    no no

  17. tamtoan
    • 3 years ago
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    the sum, not the difference ...and the sum of them is 41..do that again ?

  18. eli123
    • 3 years ago
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    4 and 5

  19. tamtoan
    • 3 years ago
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    where do you get 4 and 5 ?

  20. eli123
    • 3 years ago
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    five minus four is 1 and 4^2+5^2 is 41

  21. tamtoan
    • 3 years ago
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    that's guessing, you guess right, but it's not the way to solve :) you have to write a system of 2 equations and try to solve it.

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