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Sunshine447 Group Title

Given: In ∆ABC, segment DE is parallel to segment AC . Prove: BD over BA equals BE over BC The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally. Statement Reason 1. segment DE is parallel to segment AC 1. Given 2. Line segment BA is a transversal that intersects two parallel lines 2. Conclusion from Statement 1 3. 3. 4. ∡B ≅ ∡B 4. Reflexive Property of Equality 5. ∆ABC ~ ∆DBE 5. Angle-Angle (AA) Similarity Postulate 6. 6.

  • one year ago
  • one year ago

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  1. Sunshine447 Group Title
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    Complete the proof by entering the correct statements and reasons.

    • one year ago
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    @amistre64 @jim_thompson5910

    • one year ago
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    • one year ago
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    @Hero

    • one year ago
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    3. ∡BDE ≅ ∡BAC 3. Corresponding Angles Are Congruent

    • one year ago
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    @Hero what about 6?

    • one year ago
  7. Hero Group Title
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    Bro, giving you that is like giving you the answer.

    • one year ago
  8. Sunshine447 Group Title
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    is 6 something along the lines of ABC~DBE because they're similar triangles?

    • one year ago
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    I dont understand number 6

    • one year ago
  10. Hero Group Title
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    The last entry is always what you have to prove so 6. BD over BA equals BE over BC 6.

    • one year ago
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    Good luck figuring out the reason

    • one year ago
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