## Sunshine447 2 years ago Given: In ∆ABC, segment DE is parallel to segment AC . Prove: BD over BA equals BE over BC The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally. Statement Reason 1. segment DE is parallel to segment AC 1. Given 2. Line segment BA is a transversal that intersects two parallel lines 2. Conclusion from Statement 1 3. 3. 4. ∡B ≅ ∡B 4. Reflexive Property of Equality 5. ∆ABC ~ ∆DBE 5. Angle-Angle (AA) Similarity Postulate 6. 6.

1. Sunshine447

Complete the proof by entering the correct statements and reasons.

2. Sunshine447

@amistre64 @jim_thompson5910

3. Sunshine447

4. Sunshine447

@Hero

5. Hero

3. ∡BDE ≅ ∡BAC 3. Corresponding Angles Are Congruent

6. Sunshine447

7. Hero

Bro, giving you that is like giving you the answer.

8. Sunshine447

is 6 something along the lines of ABC~DBE because they're similar triangles?

9. Sunshine447

I dont understand number 6

10. Hero

The last entry is always what you have to prove so 6. BD over BA equals BE over BC 6.

11. Hero

Good luck figuring out the reason