At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

@shortcake1970 do you know the definition of a light year?

A light year is the distance that light travels in one Earth year.

light travels at 3*10^8 m/s

Yes that's approximately the speed of light, as @VeritasVosLiberabit said.

so it seems the 2*10^8 is meant to throw you off because it is irrelevant to finding the distance

and the distance light travels in a year is 9.47 X 10^15 i have that much

it might be better to keep your calculations in MKS units unless told otherwise.

Alright @shortcake1970 now simply multiply that answer by 50.

so do I just multiply?

Haha that's what I said.

oops yup you just answered that

Thank you!

Welcome!

Need help with anything else or are you okay?

well I do have another questions I might need help with let me write it...

Sure

Are these questions you've tried yourself? It's important you try them yourself first.

once i know which formula i can work it out myself :)

Sorry I was away for a minute. Just give me second. I'm just in the middle of something.

ok i'm having a hard time typing the formula

delta t=delta t o /square root of 1-v^2/c^2

OK I'm back. Yes\[\Delta t =\frac{ \Delta t _{0} }{ \sqrt{1-\frac{ v ^{2} }{ c ^{2} }} }\]

.90 x 10^8 s

Give me a second to calculate it.

is the answer for the previous question 4.73 x 10^17?

It should be\[9.0\times10^{-9}\]

That exponent is negative 9

oh i see

Do you? Did you spot your error?

yes i spotted the error

Great. I have to go but is there anything else before I do?

I guess not. I might be back a little later. Bye.

thank you so much.