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shortcake1970

if you were to travel to a star 50 light years from earth at a speed of 2.0 X 10 to 8th power m/s, what would you measure this distance to be?

  • one year ago
  • one year ago

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  1. calculusfunctions
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    @shortcake1970 do you know the definition of a light year?

    • one year ago
  2. calculusfunctions
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    A light year is the distance that light travels in one Earth year.

    • one year ago
  3. VeritasVosLiberabit
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    light travels at 3*10^8 m/s

    • one year ago
  4. calculusfunctions
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    Yes that's approximately the speed of light, as @VeritasVosLiberabit said.

    • one year ago
  5. VeritasVosLiberabit
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    so it seems the 2*10^8 is meant to throw you off because it is irrelevant to finding the distance

    • one year ago
  6. shortcake1970
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    and the distance light travels in a year is 9.47 X 10^15 i have that much

    • one year ago
  7. calculusfunctions
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    Now find the number of seconds in one Earth year. Yes @VeritasVosLiberabit , that is extraneous information. Not needed.

    • one year ago
  8. VeritasVosLiberabit
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    it might be better to keep your calculations in MKS units unless told otherwise.

    • one year ago
  9. calculusfunctions
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    Alright @shortcake1970 now simply multiply that answer by 50.

    • one year ago
  10. shortcake1970
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    so do I just multiply?

    • one year ago
  11. calculusfunctions
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    Haha that's what I said.

    • one year ago
  12. shortcake1970
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    oops yup you just answered that

    • one year ago
  13. shortcake1970
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    Thank you!

    • one year ago
  14. calculusfunctions
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    Welcome!

    • one year ago
  15. calculusfunctions
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    Need help with anything else or are you okay?

    • one year ago
  16. shortcake1970
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    well I do have another questions I might need help with let me write it...

    • one year ago
  17. calculusfunctions
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    Sure

    • one year ago
  18. calculusfunctions
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    Are these questions you've tried yourself? It's important you try them yourself first.

    • one year ago
  19. shortcake1970
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    a beam of a certain type of elementary particle travels at a speed of 2.8 X 10^8 m/s. at this speed the average lifetime is measured to be 2.5 X 10^-8 s. what is the particle's lifetime at rest. let me tell you what formula i was thinking of using

    • one year ago
  20. shortcake1970
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    once i know which formula i can work it out myself :)

    • one year ago
  21. calculusfunctions
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    Sorry I was away for a minute. Just give me second. I'm just in the middle of something.

    • one year ago
  22. shortcake1970
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    ok i'm having a hard time typing the formula

    • one year ago
  23. shortcake1970
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    delta t=delta t o /square root of 1-v^2/c^2

    • one year ago
  24. calculusfunctions
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    OK I'm back. Yes\[\Delta t =\frac{ \Delta t _{0} }{ \sqrt{1-\frac{ v ^{2} }{ c ^{2} }} }\]

    • one year ago
  25. calculusfunctions
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    Do you understand? \[\Delta t = 2.5\times10^{-8}s\]\[v =2.8\times10^{8}m/s\]\[c =3.0\times10^{8}m/s\]\[\Delta t _{0}=?\]Rearrange the formula first to get\[\Delta t _{0}=\Delta t \sqrt{1-\frac{ v ^{2} }{ c ^{2} }}\]

    • one year ago
  26. shortcake1970
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    .90 x 10^8 s

    • one year ago
  27. calculusfunctions
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    Give me a second to calculate it.

    • one year ago
  28. shortcake1970
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    is the answer for the previous question 4.73 x 10^17?

    • one year ago
  29. calculusfunctions
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    It should be\[9.0\times10^{-9}\]

    • one year ago
  30. calculusfunctions
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    That exponent is negative 9

    • one year ago
  31. shortcake1970
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    oh i see

    • one year ago
  32. calculusfunctions
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    Do you? Did you spot your error?

    • one year ago
  33. shortcake1970
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    yes i spotted the error

    • one year ago
  34. calculusfunctions
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    Great. I have to go but is there anything else before I do?

    • one year ago
  35. calculusfunctions
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    I guess not. I might be back a little later. Bye.

    • one year ago
  36. shortcake1970
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    thank you so much.

    • one year ago
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