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find the linear approximation of
\[f(x)=\sqrt{1-x}\] at a=0
and use it to approximate \[\sqrt{.98}\]

@hartnn Help please

agree with him ^
put x=0.02.

in general, its good to know that
\(\huge \sqrt[n]{1-x} \approx 1-nx\)

\(\huge \sqrt[n]{1 \pm x} \approx 1 \pm nx\)