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anonymous
 4 years ago
A 2.17μF capacitor is connected to a 270V, 110.0Hz line. Find the peak value of the current through the capacitor.
anonymous
 4 years ago
A 2.17μF capacitor is connected to a 270V, 110.0Hz line. Find the peak value of the current through the capacitor.

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kropot72
 4 years ago
Best ResponseYou've already chosen the best response.0Do you know how to calculate the reactance of the capacitor?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i just dont understand how to do the peak value

kropot72
 4 years ago
Best ResponseYou've already chosen the best response.0The RMS value of current is given by \[\frac{270}{666.76}amps\] The peak value is obtained by multiplying the RMS value by \[\sqrt{2}\]

kropot72
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, although I get 0.573 amps when rounded.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0welp it stays its wrong I have an example of one that is right with out the work

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A 2.11μF capacitor is connected to a 110V, 120.0Hz line. Find (a) the capacitive reactance; 628.574024849508 Ω (b) the peak value of the current through the capacitor. 174.999277175566 mA

kropot72
 4 years ago
Best ResponseYou've already chosen the best response.0(a) Is the correct answer (b) The current stated in the answer is the RMS (root mean square) value, and is not the peak value.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats prob why it was confusing me i suppose

kropot72
 4 years ago
Best ResponseYou've already chosen the best response.0@jatasia It is not stated in the questions whether or not the line voltage is the RMS or the peak value. By convention if the value of an AC voltage is stated it is regarded as an RMS value unless stated otherwise.
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