## jatasia Group Title A 2.17-μF capacitor is connected to a 270-V, 110.0-Hz line. Find the peak value of the current through the capacitor. one year ago one year ago

1. kropot72 Group Title

Do you know how to calculate the reactance of the capacitor?

2. jatasia Group Title

yep i have it 666.76

3. jatasia Group Title

i just dont understand how to do the peak value

4. kropot72 Group Title

The RMS value of current is given by $\frac{270}{666.76}amps$ The peak value is obtained by multiplying the RMS value by $\sqrt{2}$

5. jatasia Group Title

.572?

6. kropot72 Group Title

Yes, although I get 0.573 amps when rounded.

7. jatasia Group Title

welp it stays its wrong I have an example of one that is right with out the work

8. jatasia Group Title

A 2.11-μF capacitor is connected to a 110-V, 120.0-Hz line. Find (a) the capacitive reactance; 628.574024849508 Ω (b) the peak value of the current through the capacitor. 174.999277175566 mA

9. kropot72 Group Title

(a) Is the correct answer (b) The current stated in the answer is the RMS (root mean square) value, and is not the peak value.

10. jatasia Group Title

ohhh i seee

11. jatasia Group Title

thats prob why it was confusing me i suppose

12. kropot72 Group Title

@jatasia It is not stated in the questions whether or not the line voltage is the RMS or the peak value. By convention if the value of an AC voltage is stated it is regarded as an RMS value unless stated otherwise.