anonymous
  • anonymous
A 2.17-μF capacitor is connected to a 270-V, 110.0-Hz line. Find the peak value of the current through the capacitor.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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kropot72
  • kropot72
Do you know how to calculate the reactance of the capacitor?
anonymous
  • anonymous
yep i have it 666.76
anonymous
  • anonymous
i just dont understand how to do the peak value

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More answers

kropot72
  • kropot72
The RMS value of current is given by \[\frac{270}{666.76}amps\] The peak value is obtained by multiplying the RMS value by \[\sqrt{2}\]
anonymous
  • anonymous
.572?
kropot72
  • kropot72
Yes, although I get 0.573 amps when rounded.
anonymous
  • anonymous
welp it stays its wrong I have an example of one that is right with out the work
anonymous
  • anonymous
A 2.11-μF capacitor is connected to a 110-V, 120.0-Hz line. Find (a) the capacitive reactance; 628.574024849508 Ω (b) the peak value of the current through the capacitor. 174.999277175566 mA
kropot72
  • kropot72
(a) Is the correct answer (b) The current stated in the answer is the RMS (root mean square) value, and is not the peak value.
anonymous
  • anonymous
ohhh i seee
anonymous
  • anonymous
thats prob why it was confusing me i suppose
kropot72
  • kropot72
@jatasia It is not stated in the questions whether or not the line voltage is the RMS or the peak value. By convention if the value of an AC voltage is stated it is regarded as an RMS value unless stated otherwise.

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