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jatasia

A 2.17-μF capacitor is connected to a 270-V, 110.0-Hz line. Find the peak value of the current through the capacitor.

  • one year ago
  • one year ago

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  1. kropot72
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    Do you know how to calculate the reactance of the capacitor?

    • one year ago
  2. jatasia
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    yep i have it 666.76

    • one year ago
  3. jatasia
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    i just dont understand how to do the peak value

    • one year ago
  4. kropot72
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    The RMS value of current is given by \[\frac{270}{666.76}amps\] The peak value is obtained by multiplying the RMS value by \[\sqrt{2}\]

    • one year ago
  5. jatasia
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    .572?

    • one year ago
  6. kropot72
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    Yes, although I get 0.573 amps when rounded.

    • one year ago
  7. jatasia
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    welp it stays its wrong I have an example of one that is right with out the work

    • one year ago
  8. jatasia
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    A 2.11-μF capacitor is connected to a 110-V, 120.0-Hz line. Find (a) the capacitive reactance; 628.574024849508 Ω (b) the peak value of the current through the capacitor. 174.999277175566 mA

    • one year ago
  9. kropot72
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    (a) Is the correct answer (b) The current stated in the answer is the RMS (root mean square) value, and is not the peak value.

    • one year ago
  10. jatasia
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    ohhh i seee

    • one year ago
  11. jatasia
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    thats prob why it was confusing me i suppose

    • one year ago
  12. kropot72
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    @jatasia It is not stated in the questions whether or not the line voltage is the RMS or the peak value. By convention if the value of an AC voltage is stated it is regarded as an RMS value unless stated otherwise.

    • one year ago
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