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A 2.17-μF capacitor is connected to a 270-V, 110.0-Hz line. Find the peak value of the current through the capacitor.

Physics
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Do you know how to calculate the reactance of the capacitor?
yep i have it 666.76
i just dont understand how to do the peak value

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Other answers:

The RMS value of current is given by \[\frac{270}{666.76}amps\] The peak value is obtained by multiplying the RMS value by \[\sqrt{2}\]
.572?
Yes, although I get 0.573 amps when rounded.
welp it stays its wrong I have an example of one that is right with out the work
A 2.11-μF capacitor is connected to a 110-V, 120.0-Hz line. Find (a) the capacitive reactance; 628.574024849508 Ω (b) the peak value of the current through the capacitor. 174.999277175566 mA
(a) Is the correct answer (b) The current stated in the answer is the RMS (root mean square) value, and is not the peak value.
ohhh i seee
thats prob why it was confusing me i suppose
@jatasia It is not stated in the questions whether or not the line voltage is the RMS or the peak value. By convention if the value of an AC voltage is stated it is regarded as an RMS value unless stated otherwise.

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