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kenneyfamily
Group Title
solve the inequality
(2/3)  x+5  < 12
a. x >7 or x<7
b. x>7 or x< 17
c. 17<x<7
 one year ago
 one year ago
kenneyfamily Group Title
solve the inequality (2/3)  x+5  < 12 a. x >7 or x<7 b. x>7 or x< 17 c. 17<x<7
 one year ago
 one year ago

This Question is Closed

Hero Group TitleBest ResponseYou've already chosen the best response.1
Hint: Multiply both sides by 3/2
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
x+5 < 18 @Hero ??
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
if when multiply by a negative number ur equation sign must reverse be >
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
If one side represents distance and the other side has a negative number, can distance be negative?
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
i thought that was only for division?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
division still family with multiply :p
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Bro, if you multiply or divide by a negative number, it doesn't matter. You have to switch signs.
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
x+5 > 18 Now that gives us a valid equation to work with since distance (being positive) can be greater than a negative number.
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
ok so  x+5  > 18. now you subtract 5 right? so thats x > 23. thats not a choice
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Bro, the five is trapped inside the absolute value symbol. What will you do to "free" it?
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
i dont know
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
18 > x + 5 > 18 x + 5 < 18 x + 5 > 18
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
x < 18  5 x > 18  5
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
x<13 and x>23
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
but how does that help? its not a choice
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
@Hero ? sorry to bother you
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
the question is wrong :p
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
great....so my best guess? maybe c? @RadEn
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
yes, like u said before the solution should be x<13 or x>23 (dont use word "and")
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
or similar by : 23 < x < 13
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
I think the solution is all real numbers
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
I doublechecked on my calculator and on wolframalpha
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
yea, all real number :)  multiply by abs number always be negative, right ? because abs number must be positive
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Yeah, this is the type where you cannot solve for x by using normal algebra methods. You just have to look at it and realize distance will always be greater than a negative number
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
@kennyfamily, double check and make sure you posted the question correctly.
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
recheck again ur question @kenneyfamily
 one year ago
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