Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

I need help, please

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

I have attached the question
1 Attachment
we can do this
yes, could you explain it ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

ok first off z is 4, so lets forget z and replace it by 4
the volume of the first tube, the one with side \(x\) is \(4\times (\frac{1}{4}x)^2\)
why is it 1/4 ?
because your entire length is \(x\) and you are folding it in to a square so the side of the square is \(\frac{1}{4}x\)
and therefore the area of the square is \((\frac{1}{4}x)^2=\frac{x^2}{16}\) and since \(z=4\) the volume is \(4\times \frac{x^2}{16}=\frac{x^2}{4}\)
the volume of the second one is easy, since \(z=4\) it is just \(y\)
then we add them togther?
now we use the fact that \(x+y=8\) and so \(y=8-x\)
now we add them together, because now we have an expression for the volume in one variable it will be \[V(x)=\frac{x^2}{4}+8-x\]
now if this is a calculus question you can take the derivative, set it equal to zero and solve if not, you can say the vertex is at \(-\frac{b}{2a}\) with \(a=\frac{1}{4}\) and \(b=-1\)
got it
ok good this has a min at the vertex, and i guess a max at the end point of the interval, so be careful about what that is
i guess it is \([0,8]\) since \(x\) must be in there somewhere
ok, thanks alot `
Hi just quick question, why we need interval there? how did you know that there should be an inteval?

Not the answer you are looking for?

Search for more explanations.

Ask your own question