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swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0a) the sum of their squares is a large as possible; as small as possible? b) one number plus the square root of the other is a large as possible; as small as possible?

jennychan12
 2 years ago
Best ResponseYou've already chosen the best response.0i only know how to do this with optimization (calculus) x^2+y^2 =M x+y = 20 Find y in terms of x and plug it in, then take the derivative.

swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0so that's the minimum? but i don't know how to find the largest possible answer

swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0no, i did it your previous way lol. I put the primary equation as x^2+y^2= S and the secondary equation as x+y=20 but idk if that's correct.

jennychan12
 2 years ago
Best ResponseYou've already chosen the best response.0yeah, that's correct, then solve for one of the variables and plug it into the S equation

swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0the S equation or the S' equation?

jennychan12
 2 years ago
Best ResponseYou've already chosen the best response.0plug it into the S equation, simplify then take the derivative (S')

swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0Oh i figured it out lol!!! But i don't know how to solve for part b :(

jennychan12
 2 years ago
Best ResponseYou've already chosen the best response.0x+sqrt(y) = M try that?

jennychan12
 2 years ago
Best ResponseYou've already chosen the best response.0using x+y = 20 plug in, same things...? dunno if it'll work, but....
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