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jennychan12Best ResponseYou've already chosen the best response.0
is that log base 5? if so just divide out the bases so you get 2x = 2x7 solve for x
 one year ago

christinaxxxBest ResponseYou've already chosen the best response.0
it is base five, but what about the minus 1?
 one year ago

jennychan12Best ResponseYou've already chosen the best response.0
move the logbase5(2x7) to the other side and move the 1 over. try from there?
 one year ago

christinaxxxBest ResponseYou've already chosen the best response.0
i did and i got x=3 and i feel like that's wrong
 one year ago

jennychan12Best ResponseYou've already chosen the best response.0
really? i got x = 3.
 one year ago

christinaxxxBest ResponseYou've already chosen the best response.0
this is what i did. 1=logbase5 (2x+7/2x) (2x+7)/(2x)= 5^1 (2x+7)/(2x)=1/5 then i cross multiplied and got 5(2x+7)=1(2x) 10x+35=2x 11x+35=2 11x=33 x=3 righttttt?
 one year ago

jennychan12Best ResponseYou've already chosen the best response.0
Log5 (2x) – 1 = log5 (2x7) i meant like move the 1 to the right and the logbase5(2x7) to the left so you get (2x)/(2x7) = 5 i got 3, but neither 3 nor 3 work as answers. and your 2x+7 should be a 7...unless u wrote the question wrong...
 one year ago

christinaxxxBest ResponseYou've already chosen the best response.0
nope, my question is from a worksheet. no error in my copying it down. but the negative one would be the exponent of the base 5, wouldn't it? so you'd have to raise five to the negative one?
 one year ago

jennychan12Best ResponseYou've already chosen the best response.0
i dunno why we're getting diff answers cuz u could do it multiple ways
 one year ago
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