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HEEELLLPPPP PLEASEEEE!
A sound wave is modeled with the equation y =1/4 cos 2pi/3 theta
a. Find the period. Explain your method.
b. Find the amplitude. Explain your method
 one year ago
 one year ago
HEEELLLPPPP PLEASEEEE! A sound wave is modeled with the equation y =1/4 cos 2pi/3 theta a. Find the period. Explain your method. b. Find the amplitude. Explain your method
 one year ago
 one year ago

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ShadowysBest ResponseYou've already chosen the best response.1
note that waves can be of general eq, y=r cos wt, where r is the amplitude, w the angular velocity and t is the time parameter.
 one year ago

VeritasVosLiberabitBest ResponseYou've already chosen the best response.0
This looks like physics.
 one year ago

zoey123Best ResponseYou've already chosen the best response.0
well do you know the answer?
 one year ago

VeritasVosLiberabitBest ResponseYou've already chosen the best response.0
Yes but just so you know. This is a physics question not mathematics.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
cross reference your eq with the general eq above.
 one year ago

zoey123Best ResponseYou've already chosen the best response.0
ok well can i have the answer?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
did you try to do it yourself first?
 one year ago

zoey123Best ResponseYou've already chosen the best response.0
yes and i am beyind confused :/
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
what did you get? by the way, your equation didnot involve time ......
 one year ago

zoey123Best ResponseYou've already chosen the best response.0
cause thats not what it asked for i just need the period of the graph and what the amplitude would be you do this by using trig and i got the amplitude is 4 and the period is 2 but i dont think that is right
 one year ago

VeritasVosLiberabitBest ResponseYou've already chosen the best response.0
\[\omega = \frac{ 2\pi }{ T }\]
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
amplitude, A through a mathematical analysis, the amplitude is the highest/lowest point of the curve. \(y =\frac{1}{4}\cos \frac{2\pi}{3}{ \theta}\) \(y' =\frac{1}{4}(\frac{2\pi}{3})\sin \frac{2\pi}{3}{ \theta}\) let y'=0, \(\sin \frac{2\pi}{3}{ \theta}=0\) \(\theta=0\) y=1/4=A you follow?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
yup, now, \(y'=\omega\) the period is the time for two wavecrest, i.e. two amplitude, also aka two y'=0 so you find the w for two successive max points and you'll get it.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
on second thought, where is the time parameter=.=
 one year ago
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