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mattster9321

  • 3 years ago

If the area of the triangle is 36cm2, what is the length, in cm, of leg xy. i missed class and i cant figure it out

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  1. PhoenixFire
    • 3 years ago
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    Leg xy is where? Can you draw a picture? What's the height of the triangle?

  2. mattster9321
    • 3 years ago
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    it doesnt give me one i can try and draw one

  3. PhoenixFire
    • 3 years ago
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    \[A={1 \over 2}bh\] |dw:1354695650945:dw|

  4. mattster9321
    • 3 years ago
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    |dw:1354695794159:dw|

  5. mattster9321
    • 3 years ago
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    thats what it gives me

  6. mattster9321
    • 3 years ago
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    XY is on the bottom by the way forgot to add all that

  7. PhoenixFire
    • 3 years ago
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    |dw:1354695885781:dw|

  8. mattster9321
    • 3 years ago
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    no it is not. all it gives me is the area which is 36cm2

  9. mattster9321
    • 3 years ago
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    i want to say its 12 but not sure

  10. winterfez
    • 3 years ago
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    since 36 is a perfect square.\[ \frac{ 1 }{ 2}(12)(6)=36cm^{2}\]

  11. winterfez
    • 3 years ago
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    the base has to be 12

  12. mattster9321
    • 3 years ago
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    thats what im thinking

  13. mattster9321
    • 3 years ago
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    it gives me 5 different answers to pick from 6,9,12,18,24

  14. PhoenixFire
    • 3 years ago
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    No. \[(0.5)(24)(3)=36\]

  15. mattster9321
    • 3 years ago
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    so your saying 24 would be the length of leg xy?

  16. tamtoan
    • 3 years ago
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    @winterfez, that's incorrect, since 72 = 36x2 = 9x8= 18x4 and so on.. , many possibilities , i think phoenixfire leads him on the right track, need more info on this to solve.

  17. winterfez
    • 3 years ago
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    well for this question you need to know either the height or the base

  18. PhoenixFire
    • 3 years ago
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    Could be a lot of different numbers. You're missing information.

  19. mattster9321
    • 3 years ago
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    i can take a picture of the diagram on my cell and upload it for you guys to see the diagram given to me

  20. winterfez
    • 3 years ago
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    \[\frac{ 1 }{ 2}bh=36cm ^{2}\] I don't think you can find from this equation. Like PhoenixFire point out you need to know 1 more information for either base or height

  21. mattster9321
    • 3 years ago
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    give me a few i will upload a photo with everything given to me

  22. mattster9321
    • 3 years ago
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  23. mattster9321
    • 3 years ago
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    that is what they have given me to work with

  24. PhoenixFire
    • 3 years ago
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    Leg XY is twice as long as YZ. That's the info we needed. Let b=XY and h=2b \[A={1 \over 2}2b^2=b^2\]\[\sqrt{36}=b=6\] Your leg XY=6 and YZ=12

  25. tamtoan
    • 3 years ago
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    phoenixfire, you got the other way around :) XY is twice as long as YZ :)

  26. mattster9321
    • 3 years ago
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    sorry bout that. my bad. this is my first time using this site. i thought i mentioned it. but thank you very much PhoenixFire, tamotan, and winterfez.

  27. mattster9321
    • 3 years ago
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    so the length of leg xy is 24?

  28. PhoenixFire
    • 3 years ago
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    I see. b=2h h=YZ \[A={1 \over 2}2h^2=h^2\]\[h=\sqrt{36}=6\] \[b=2h=2(6)=12\] XY = 12

  29. tamtoan
    • 3 years ago
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    there :)

  30. PhoenixFire
    • 3 years ago
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    My bad for that mistake. haha, Thanks @tamtoan

  31. mattster9321
    • 3 years ago
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    alright so its 12 like i thought lol:) i was confused. normally im good at math. but missing class and then getting this confused me

  32. tamtoan
    • 3 years ago
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    np phoenixfire :) i made mistakes all the time :) sometimes it's too easy that we are careless, anyway, good night all, bed time for me :)

  33. mattster9321
    • 3 years ago
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    thank you both for helping me. i did become fans and i think gave a medal? but thanks alot!!!

  34. PhoenixFire
    • 3 years ago
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    np :) Good Luck

  35. mattster9321
    • 3 years ago
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    thank you

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