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(Ar Nitrogen/Mr NaNo3) x mass of NaNO3

Ar stands for what?

mass of relative atom

Mr is "mass of relative molecule"

ok

no need to times 100g?

do you have a periodic table?

yes

wait a moment

Na=23.0g
N=14.0g
O=16.0g

why 23g Na?? not NaNO3?

but my idea is this...
|dw:1354705910345:dw|

our interest is in the element Na and N in the compound. the ratio of these elements is 1:1

uhhh...what do you mean?

the compound contains 100g of Na. it did not say the compound NaNO3 weighs 100g.

yes sodium is Na.., so 100 is mass of Na

represent mass of Na

@sirm3d okay, how about part b?
@gerryliyana thanks, I got it :) part b please

4.6*(10H2O/Na2) ?

mass of 10 moles of water is 10 x 18g = 180 g

we convert 4.6 g Na to g H2O by the mass ratio in the compound (180 g H2O / 23 g Na)

but there are two Na atom.... Na2Co3

sorry for typing mistakes, it should be Na2CO3 10H2O

sorry, missed that two Na. Mass of Na in compound is 46 g. use the mass ratio 180g H2O / 46g Na

|dw:1354706692310:dw|

right.

thanks. How about part c?

I got this one

i got 63.5g M

so what is the formula about finding relative atomic mass of M?

it is the mass of M relative to the mass of O

there are 1 atom of M, right?

so M is copper....

mass of M=79.87g and the relative atomic mass is ...?

how can you get the answer?

you cannot give the actual mass of M in the compound MO if you do not have the actual mass of MO.

16.0g O x 79.87g M / 20.13g O = 63.5g M

yep. that's how you convert the given.

|dw:1354708533879:dw| observe how i got rid of g O and change it to g M

I know it
is the answer of part d 168 g M?

are you here?

1 got 132.32 g M

ummm......what are your steps?

g M in MCl = 268.88g-5.68g=21.2g M

mass ratio is 21.2g M / 5.68g Cl

ummmm...you get something wrong....
is 26.88g instead of 268.88g

sorry. typo error.

relative mass of Cl = 35.453g

just take the relative mass of Cl =35.5g

35.5g Cl x 21.2g M / 5.68g Cl = 132.5g M

M = Cs

why 21.2 g?

26.88g-5.68g?

okay I got it. Thank you very much. :)

yep. 26.88g - 5.68g = 21.2g

hmm. 0.213 g O2 used in the process.