A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
(a) What is the mass of nitrogen present in the sample of sodium nitrate (NaNO3) which contains 100g of sodium?
(b) What is the mass of water of crystallization present in the sample of sodium carbonate10water (Ma2CO3·10H2O) which contains 4.6g of sodium?
(c) A metal oxide MO contains 79.87% by mass of the metal M. Find the relative atomic mass of M.
(d) 26.88g of a metal chloride MCl contains 5.68 g of chlorine. Find the relative atomic mass of the metal M.
anonymous
 3 years ago
(a) What is the mass of nitrogen present in the sample of sodium nitrate (NaNO3) which contains 100g of sodium? (b) What is the mass of water of crystallization present in the sample of sodium carbonate10water (Ma2CO3·10H2O) which contains 4.6g of sodium? (c) A metal oxide MO contains 79.87% by mass of the metal M. Find the relative atomic mass of M. (d) 26.88g of a metal chloride MCl contains 5.68 g of chlorine. Find the relative atomic mass of the metal M.

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(Ar Nitrogen/Mr NaNo3) x mass of NaNO3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0mass of relative atom

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Mr is "mass of relative molecule"

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no need to times 100g?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you have a periodic table?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large m \text { N}=100g \text { Na} \times \frac{ 14g \text{ N} }{ 23g \text { Na} } \approx 61g \text { N}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Na=23.0g N=14.0g O=16.0g

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why 23g Na?? not NaNO3?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but my idea is this... dw:1354705910345:dw

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1our interest is in the element Na and N in the compound. the ratio of these elements is 1:1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0uhhh...what do you mean?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1the compound contains 100g of Na. it did not say the compound NaNO3 weighs 100g.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes sodium is Na.., so 100 is mass of Na

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@sirm3d so it depends on the question asking about the mass of something which contains how many grams of that thing, right? @gerryliyana that hundred of sodium represents what? the mass or the weight?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1yes. be careful of the question. if the 100g is the mass of the compound NaNO3, then we need to compute the mass on Na in the compound.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@sirm3d okay, how about part b? @gerryliyana thanks, I got it :) part b please

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1same thing. The mass of Na in the compound, sodium carbonate decahydrate, is 23g. we compute the total mass of water molecules in the compound

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1mass of 10 moles of water is 10 x 18g = 180 g

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1we convert 4.6 g Na to g H2O by the mass ratio in the compound (180 g H2O / 23 g Na)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but there are two Na atom.... Na2Co3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry for typing mistakes, it should be Na2CO3 10H2O

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1sorry, missed that two Na. Mass of Na in compound is 46 g. use the mass ratio 180g H2O / 46g Na

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1354706692310:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks. How about part c?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1assume 100g mass of compound MO. Mass of M in 100g compound is 79.87 g, mass of O in 100g compound is 20.13 g.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so what is the formula about finding relative atomic mass of M?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there is no answer on my textbook. I cannot ask my teacher since I will have Chemistry examination tonight.

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1it is the mass of M relative to the mass of O

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there are 1 atom of M, right?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1yes, 1:1 ratio. so the mass of the oxygen in MO is 16g. the mass of M relative to 16g O present in the compound is the relative mass of M

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0mass of M=79.87g and the relative atomic mass is ...?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1if there is 1 mol of MO, the mass of M is 63.5 g. if there are 2 mol of MO, the mass of M is 127g. relative mass means mass in ONE mol of the compound.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how can you get the answer?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1we assumed that IF there are 100g of MO, clearly 79.77% of that mass belongs to M. you would arrive at the same result if you assume that the starting mass of MO is 20g. In this 20g MO, the mass of M is 79.87% of 20g while 20.13% of 20g is the mass of O.

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1you cannot give the actual mass of M in the compound MO if you do not have the actual mass of MO.

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1i'll give an analogy just to be clear with the "relative" mass. Suppose you got 90% of the questions in your exam, can you tell me how many correct answers you got?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if there were 100 questions in my exam, I got 90 questions correct. I know why you assume 100 g be the mass of the compound MO and the ratio is 1:1 total mass =100 g mass of M=79.87 g mass of O=20.13 g relative atomic mass of O=16.0 g But I am confusing how to get the relative atomic mass of M...... I still cannot get you idea about M...

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1we convert the relative atomic mass of O = 16.0g to relative atomic mass of M using the available masses of 79.87g M and 20.13g O.

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.116.0g O x 79.87g M / 20.13g O = 63.5g M

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the relative atomic mass of O is known and ask for the relative atomic mass of M, we need to make the mass of O be the denominator and mass of M be the numerator. If the relative atomic mass of M is known and ask for the relative atomic mass of O, we need to make the mass of M be the denominator and mass of O be the numerator. is it?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1yep. that's how you convert the given.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you for correcting my concepts and I am working with part d, I will give you response when I get my answer and you check is my answer correct or not

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354708533879:dw observe how i got rid of g O and change it to g M

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I know it is the answer of part d 168 g M?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ummm......what are your steps?

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1g M in MCl = 268.88g5.68g=21.2g M

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1mass ratio is 21.2g M / 5.68g Cl

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ummmm...you get something wrong.... is 26.88g instead of 268.88g

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1relative mass of Cl = 35.453g

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just take the relative mass of Cl =35.5g

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.135.5g Cl x 21.2g M / 5.68g Cl = 132.5g M

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay I got it. Thank you very much. :)

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1yep. 26.88g  5.68g = 21.2g

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01.200 g of a compound containing only C, H and O gave 1.173 g of CO2 and 0.240 g of H2O on complete combustion. Find the empirical formula of the compound.

sirm3d
 3 years ago
Best ResponseYou've already chosen the best response.1hmm. 0.213 g O2 used in the process.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.