Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

moongazer

  • 2 years ago

The slope of a line through A(-1,1) is 3. Locate the point on this line that is 2sqrt3 from A.

  • This Question is Closed
  1. moongazer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where did you get that fromula?

  2. moongazer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Yahoo!

  3. Yahoo!
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    u know Distance Formula

  4. moongazer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yup :)

  5. Yahoo!
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let that Point Be B (x , y ) d = 2sqrt3 A (-1,1) nw use that Formula

  6. moongazer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got x^2 + 2x - 10 + y^2 - 2y = 0 @Yahoo!

  7. moongazer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Yahoo! are you still there?

  8. moongazer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    help please :)

  9. philo1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I got \[(-1-\frac{ \sqrt{30} }{ 4 }, -1-12\frac{ \sqrt{30} }{ 4 })\] and \[(-1+\frac{ \sqrt{30} }{ 4 }, -1+12\frac{ \sqrt{30} }{ 4 })\]

  10. moongazer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @philo1234 how did you do it?

  11. philo1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Those 12 should be 3

  12. philo1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I made 2 equations: 1. Using the slope equation: \[\frac{ y-1 }{ x+1 } = 3\] 2. Then used the distance formula to make the second equation: \[2\sqrt{3} = \sqrt{(y-1)^2 + (x+1)^2}\] Do you follow so far?

  13. philo1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    3. The I solve for y in the first equation and substitute it in equation 2: \[y = 3x+4\] Substitute in equations 2: \[2\sqrt{3} = \sqrt{(3x+4-1)^2 +(x+1)^2}\] 4. Square both sides to get rid of the parentheses: \[(2\sqrt{3})^2 = (3x+3)^2 +(x+1)^2\] 5. Multiply out everything, put all the values on one side then solve for x using the quadratic formula: \[12 =10x^{2}+20x+10\]

  14. philo1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Do you understand how I got this?

  15. philo1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @moongazer

  16. philo1234
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    are u there @moongazer

  17. moongazer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm back sory for the late reply :)

  18. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.