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alexyn

  • 3 years ago

If cos x = cot x. then what is csc x?

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  1. alexyn
    • 3 years ago
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    Thats what the question asked

  2. neba.zi
    • 3 years ago
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    cscx=1

  3. alexyn
    • 3 years ago
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    Thanks Neba.zi. Can we do one more?

  4. neba.zi
    • 3 years ago
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    Of course go on!!!

  5. anonymous
    • 3 years ago
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    if \(\cos(x)=\cot(x)\) then \[\cos(x)=\frac{\cos(x)}{\sin(x)}\] and so \[\cos(x)\sin(x)=\cos(x)\] \[\cos(x)\sin(x)-\cos(x)=0\] \[\cos(x)(\sin(x)-1)=0\] \[cos(x)=0\implies x=\frac{\pi}{2}\] \[\sin(x)=1\implies x=\frac{\pi}{2}\]

  6. alexyn
    • 3 years ago
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    ok. if (sin x cot x) = 1. What is cos x?

  7. alexyn
    • 3 years ago
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    Thanks Satellite

  8. neba.zi
    • 3 years ago
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    cosx=1

  9. neba.zi
    • 3 years ago
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    cotx=cosx/sinx;sinx*cotx=(sinx)(cosx/sinx) cancel out sinx u left with cosx=1

  10. alexyn
    • 3 years ago
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    Thanks a lot ^-^

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