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alexyn
 2 years ago
Best ResponseYou've already chosen the best response.0Thats what the question asked

alexyn
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks Neba.zi. Can we do one more?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1if \(\cos(x)=\cot(x)\) then \[\cos(x)=\frac{\cos(x)}{\sin(x)}\] and so \[\cos(x)\sin(x)=\cos(x)\] \[\cos(x)\sin(x)\cos(x)=0\] \[\cos(x)(\sin(x)1)=0\] \[cos(x)=0\implies x=\frac{\pi}{2}\] \[\sin(x)=1\implies x=\frac{\pi}{2}\]

alexyn
 2 years ago
Best ResponseYou've already chosen the best response.0ok. if (sin x cot x) = 1. What is cos x?

neba.zi
 2 years ago
Best ResponseYou've already chosen the best response.1cotx=cosx/sinx;sinx*cotx=(sinx)(cosx/sinx) cancel out sinx u left with cosx=1
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