Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Nanoman
Group Title
How many grams of C8H18 are needed to produce 100g CO2 in the following equation?
 one year ago
 one year ago
Nanoman Group Title
How many grams of C8H18 are needed to produce 100g CO2 in the following equation?
 one year ago
 one year ago

This Question is Closed

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
I have my work included in this.
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
@Callisto @Preetha
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
Is the equation of the reaction given?
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
oh yes, 2C8H18 + 25 O2 yields 16 CO2 + 18H2O
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
Sorry, I forgot to include that part
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
Don't worry :) \[2C_8H_{18} + 25O_2 \rightarrow 16CO_2 +18H_2O\] no. of mole of CO2 produced required = 100/(12.0+16.0x2) = a No. of mole of C8H18 required = No. of mole of CO2 x (2/16) = a/8 = b Mass of C8H18 required = no. of mole of C8H18 required x (12.0x8 + 1.0x18) = b x (12.0x8 + 1.0x18) = answer you need. Is it clear?
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
That seems generally what I did
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
Thanks Callisto, that was the same result I got!
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.2
You're welcome. :)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.