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 2 years ago
I guess I'm just being stupid but can someone help me solve these 3 linear equations??? I keep getting no solutions..
 2 years ago
I guess I'm just being stupid but can someone help me solve these 3 linear equations??? I keep getting no solutions..

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bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.17=25a5b+c 2=ab+c 5=9a+3b+c

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.1Find the equation of the parabola y=ax2 (square)+bx+c that passes through the points (5, 7) (1,2) and (3,5) find a, b, and c that was the original question

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=7%3D25a5b%2Bc%2C+2%3Dab%2Bc%2C+5%3D9a%2B3b%2Bc

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1@amistre64 has a nicer method for doing this ask him

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.1oh cool you can use wolf for this!

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1given a set of points such that the x components create a set of elements: {\(x_1,x_2,...,x_n\)} and the set of y components create a set of elements: {\(y_1,y_2,...,y_n\)} we can create a polynomial by constructing it in this manner:\[y=c_0+c_1(xx_1)+c_2(xx_1)(xx_2)+...+c_k(xx_1)(xx_2)...(xx_k)\] :)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1(5, 7) (1,2) and (3,5) x = {5,1,3} ; y={7,2,5} y = c0 + c1(x+5) + c2(x+5)(x+1) fit the points into it and we can construct the coeffs one by one since the unknown zero out all but one of them 7 = c0 + c1(5+5) + c2(5+5)(5+1) 7 = c0 2 = 7 + c1(1+5) + c2(1+5)(1+1) 9 = c1(4) 9/4 = c1 3 = 7  9(3+5)/4 + c2(3+5)(3+1) 4 = 18 + c2(8)(4) 14 = c2(32) 7/16 = c2 y = 7  9(x+5)/4 + 7(x+5)(x+1)/16 and expand if wanted to get: (7x^2 + 6x 33)/16 if i did the mathing right

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1now i gotta dbl chk it all lol

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.13,5 ; not 3,3 5 = 7  9(3+5)/4 + c2(3+5)(3+1) 2 = 18 + c2(8)(4) 16 = c2(32) 1/2 = c2 y = 7  9(x+5)/4 + (x+5)(x+1)/2 = (2x^2+3x7)/4 which now matches the wolf ;)
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