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bahrom7893
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I guess I'm just being stupid but can someone help me solve these 3 linear equations??? I keep getting no solutions..
 one year ago
 one year ago
bahrom7893 Group Title
I guess I'm just being stupid but can someone help me solve these 3 linear equations??? I keep getting no solutions..
 one year ago
 one year ago

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bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
7=25a5b+c 2=ab+c 5=9a+3b+c
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
Find the equation of the parabola y=ax2 (square)+bx+c that passes through the points (5, 7) (1,2) and (3,5) find a, b, and c that was the original question
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=7%3D25a5b%2Bc%2C+2%3Dab%2Bc%2C+5%3D9a%2B3b%2Bc
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
@amistre64 has a nicer method for doing this ask him
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
oh cool you can use wolf for this!
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
i didn't know that
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
given a set of points such that the x components create a set of elements: {\(x_1,x_2,...,x_n\)} and the set of y components create a set of elements: {\(y_1,y_2,...,y_n\)} we can create a polynomial by constructing it in this manner:\[y=c_0+c_1(xx_1)+c_2(xx_1)(xx_2)+...+c_k(xx_1)(xx_2)...(xx_k)\] :)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
(5, 7) (1,2) and (3,5) x = {5,1,3} ; y={7,2,5} y = c0 + c1(x+5) + c2(x+5)(x+1) fit the points into it and we can construct the coeffs one by one since the unknown zero out all but one of them 7 = c0 + c1(5+5) + c2(5+5)(5+1) 7 = c0 2 = 7 + c1(1+5) + c2(1+5)(1+1) 9 = c1(4) 9/4 = c1 3 = 7  9(3+5)/4 + c2(3+5)(3+1) 4 = 18 + c2(8)(4) 14 = c2(32) 7/16 = c2 y = 7  9(x+5)/4 + 7(x+5)(x+1)/16 and expand if wanted to get: (7x^2 + 6x 33)/16 if i did the mathing right
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
now i gotta dbl chk it all lol
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
3,5 ; not 3,3 5 = 7  9(3+5)/4 + c2(3+5)(3+1) 2 = 18 + c2(8)(4) 16 = c2(32) 1/2 = c2 y = 7  9(x+5)/4 + (x+5)(x+1)/2 = (2x^2+3x7)/4 which now matches the wolf ;)
 one year ago
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