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## marixoxo76 2 years ago 13r^-4(r^-5)^5/8(r^2)^-2 solve with steps please.

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1. marixoxo76

$\frac{ 13r ^{-4}(r ^{-5})^{5} }{ 8(r ^{2})^{-2} }$

2. nickersia

$\frac{ 13*\frac{ 1 }{ r ^{4} } (\frac{ 1 }{ r ^{5} })^{5} }{ 8*\frac{ 1 }{ (r ^{2})^{2} } }$ Do you know how to do that?

3. marixoxo76

Not really... can you explain please?

4. nickersia

$r ^{-100} = \frac{ 1 }{ r ^{100} }$ Is that clear?

5. nickersia

$r ^{-4} = \frac{ 1 }{ r ^{4} }$

6. nickersia

So now you have to simplify it $\frac{ 13 *\frac{ 1 }{ r ^{4} * r ^{25} } }{ 8 * \frac{ 1 }{ r ^{4} } }$ 25 because 5*5 = 25 $\frac{ 13*\frac{ 1 }{ r ^{29} } }{ 8 * \frac{ 1 }{ r ^{4} } }$ $\frac{ \frac{ 13 }{ r ^{29} } }{ \frac{ 8 }{ r ^{4} } }$ (very up number is 13, hard to read) $\frac{ 13 * r ^{4} }{ 8 * r ^{29} }$ 29-4=25 $\frac{ 13 }{ 8r ^{25} }$ That should be resoult :)

7. marixoxo76

ah, perfect! thank you so much i was struggling with problems like these thanks got it :)

8. nickersia

Nice to hear that! Good luck!

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