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HELP ME PLEASE! Write a polynomial function in standard form with zeros at 5, 2, and 1.
 one year ago
 one year ago
HELP ME PLEASE! Write a polynomial function in standard form with zeros at 5, 2, and 1.
 one year ago
 one year ago

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mathstudent55Best ResponseYou've already chosen the best response.0
Think of it this way, instead of solving a polynomial equation and getting x=a, x=b, x=c, you have the answer and you're going backwards. If you had a polynomial equation that factored into (x  3)(x + 5)(x 2)= 0, the next step would be x 3 = 0 or x + 5 = 0 or x  2 = 0, and the answer would be x = 3 or x = 5 or x = 2
 one year ago

shahzadjalbaniBest ResponseYou've already chosen the best response.0
zero means x=0 x=2 or x2=0 x=5or x5=0 (x)(x2)(x5) The resultant equation is \[x^{3}7x^{2}+10x\]
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.0
Now look at the last line and go backwards. In your problem here, you are given x = 5, x = 2, x = 1 Go 1 step back: x  5 = 0 or x  2 = 0 or x  1 = 0 Go 1 more step back (x  5)(x  2)(x  1) =0 Now multiply these 3 binomials together, collect like terms and write the answer in descending order of the power of x.
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.0
Be careful, shahzadjalbani misread the problem and thinks there is a zero at 0. His solution is correct for the problem he solved, but it's not your problem.
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.0
Multiply the first two binomials using foil. Then multiply by the third one.
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.0
(x  5)(x  2)(x  1) = 0 (x^2  2x  5x + 10)(x  1) = 0 (x^2  7x + 10)(x  1) = 0 continue...
 one year ago

shahzadjalbaniBest ResponseYou've already chosen the best response.0
oh sorry x=1 x1=0 x=2 x2=0 x=5 x5=0 Multiply (x1)(x5)(x2) The result would be x^38x^{2}+17x10
 one year ago

shahzadjalbaniBest ResponseYou've already chosen the best response.0
Good Luck @kerstie
 one year ago
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