Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
method one solve \[x^3=8\] \[x^38=0\] \[(x2)(x^2+2x+4)=0\] quadratic formula will give the solutions to \[x^2+2x+4=0\]
 one year ago

scottman Group TitleBest ResponseYou've already chosen the best response.0
I see and so 2 is one root and the other 2 complex numbers will be the other 2 roots?
 one year ago

kerstie Group TitleBest ResponseYou've already chosen the best response.0
@Satellite73
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
method two solve \(x^3=1\) and multiply by two since one solution is 1, divide the unit circle in two three equal parts one is at 1, the other two are \(\frac{1}{2}+\frac{\sqrt{3}}{2}i\) and its conjugate \(\frac{1}{2}\frac{\sqrt{3}}{2}i\) multiply these numbers by 2
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
to answer your question, yes, the solution to the quadratic will give you the two complex roots
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
@kerstie hello
 one year ago

scottman Group TitleBest ResponseYou've already chosen the best response.0
ok thanks a lot, you helped me greatly
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.