A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Find the exact value of the area under one arch of the curve y(t) = V_0sin(wt). Assume V_0 and w are positive constants.
anonymous
 3 years ago
Find the exact value of the area under one arch of the curve y(t) = V_0sin(wt). Assume V_0 and w are positive constants.

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What problem are you having with that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how to find the area of one arch of the curve

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Integrate from t=0 to t= pi/w the function y(t) = V_0sin(wt)....the period of the sine function is 2*pi normally but the period in the case is 2pi/w, and for one arch of the curve, that is one half period, so the half period = pi/w. So then you just need to do the integral and evaluate at those limits. (0 to pi/w)......good luck.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.