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Find the exact value of the area under one arch of the curve y(t) = V_0sin(wt). Assume V_0 and w are positive constants.
 one year ago
 one year ago
Find the exact value of the area under one arch of the curve y(t) = V_0sin(wt). Assume V_0 and w are positive constants.
 one year ago
 one year ago

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SomeBlokeBest ResponseYou've already chosen the best response.0
What problem are you having with that?
 one year ago

LdanielBest ResponseYou've already chosen the best response.0
how to find the area of one arch of the curve
 one year ago

dishman1966Best ResponseYou've already chosen the best response.0
Integrate from t=0 to t= pi/w the function y(t) = V_0sin(wt)....the period of the sine function is 2*pi normally but the period in the case is 2pi/w, and for one arch of the curve, that is one half period, so the half period = pi/w. So then you just need to do the integral and evaluate at those limits. (0 to pi/w)......good luck.
 one year ago
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