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samnatha
 3 years ago
pleasssse helpp me !
find the value of K for which x + 4y + K = 0 is a tangent to x^2 + y^2  2x + 2y  15 = 0
samnatha
 3 years ago
pleasssse helpp me ! find the value of K for which x + 4y + K = 0 is a tangent to x^2 + y^2  2x + 2y  15 = 0

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malevolence19
 3 years ago
Best ResponseYou've already chosen the best response.1You need implicit differentiation \[2x+\frac{dy}{dx}2y2+2 \frac{dy}{dx}=0 \implies x2+\frac{dy}{dx}(y+2)=0 \implies \frac{dy}{dx}=\frac{2x}{y+2}\] \[yy_0=\left. \frac{dy}{dx} \right\_{x_0,y_0}(xx_0)\] So you need a point. Then you can find the equation then identify K

samnatha
 3 years ago
Best ResponseYou've already chosen the best response.0see i can't do it that way as we have not done differentiation so it confuses me i know there is another way like you can rearrange the first equation so that x = .... and then sub it into the other one but after i do that i'm no sure what to do

malevolence19
 3 years ago
Best ResponseYou've already chosen the best response.1If you just solve the first one for x: \[x=4yK \] And plug it in you get: \[(4y+K)^2+y^2+2(4y+K)+2y=0\] From this you can solve for K in terms of y. As long as you know the slope and everything is write for the original line this will give you the value which allows it to cross tangential. But the slope changes every small increment you move so I don't feel convinced that the slope (in general) can just be 1/4...

samnatha
 3 years ago
Best ResponseYou've already chosen the best response.0how do i get the slope from that ?

samnatha
 3 years ago
Best ResponseYou've already chosen the best response.0do i multiply out the equations so i get this \[16y ^{2} + 8yk + k ^{2} + y ^{2} + 8y + 2k + 2y  15\]
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