A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0the mass of an automobile is 1160 kg, and the distance between its front and rear axles is 2.54m. The center of gravity of the car is between the front and rear tires, and the horizontal distance between the center of gravity and the front axle is 1.02 m. Determine the normal force that the ground applies to (A) each of the two front wheels an to (B) each of the two rear wheels.

cj7529
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1354750892209:dw Weight of the car W = mg = 1160 x 9.81 =11379.6N effectively you have a torque or moment problem now: dw:1354751216998:dw So, Force x distance = torque F1x(2.541.02)=F2x1.02 and because the upwards force balances the downwards force: F1 +F2 = W Now you have 2 equations for F1 and F2 and you can solve them simultaneously you ok from here????? =)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.