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Studentc14 Group Title

Functions! Please help, very important! :) (file attached)

  • one year ago
  • one year ago

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  1. Studentc14 Group Title
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    • one year ago
  2. slaaibak Group Title
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    f . g = h f = 3x + 5 h = 3x^2 + 3x + 2 so f(g(x)) = 3x^2 + 3x + 2 That means: 3(g(x)) + 5 = 3x^2 + 3x + 2 By inspection: g(x) = x^2 + x - 1

    • one year ago
  3. Studentc14 Group Title
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    what's inspection, sorry?

    • one year ago
  4. slaaibak Group Title
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    Figuring it out by looking at it

    • one year ago
  5. Studentc14 Group Title
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    I don't follow, how you get this part? 3(g(x)) + 5 = 3x^2 + 3x + 2

    • one year ago
  6. slaaibak Group Title
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    we know h(x) = 3x^2 + 3x +2 --------> (1) and we know f.g = f(g(x)) but f(x) = 3x + 5, therefore f(g(x)) = 3(g(x)) + 5 --------> (2) and we know that f.g = h ----> f(g(x)) = h(x) therefore: (1) = (2) 3(g(x)) + 5 = 3x^2 + 3x +2

    • one year ago
  7. Studentc14 Group Title
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    ohkay, and then you can kinda just look at it and like guess and check and see that x^2+x-1 works for g, right?

    • one year ago
  8. slaaibak Group Title
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    Yes. Or you can just solve G like a normal variable: 3(g(x)) + 5 = 3x^2 + 3x +2 Substract 5 on both sides: 3(g(x)) = 3x^2 + 3x -3 Divide by 3: g(x) = x^2 + x - 1

    • one year ago
  9. Studentc14 Group Title
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    oh! that's much clearer. thank you so much!

    • one year ago
  10. slaaibak Group Title
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    shot

    • one year ago
  11. Studentc14 Group Title
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    shot?

    • one year ago
  12. slaaibak Group Title
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    haha, colloquial for "cool, no problem"

    • one year ago
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