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Studentc14
Group Title
Functions! Please help, very important! :)
(file attached)
 one year ago
 one year ago
Studentc14 Group Title
Functions! Please help, very important! :) (file attached)
 one year ago
 one year ago

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slaaibak Group TitleBest ResponseYou've already chosen the best response.1
f . g = h f = 3x + 5 h = 3x^2 + 3x + 2 so f(g(x)) = 3x^2 + 3x + 2 That means: 3(g(x)) + 5 = 3x^2 + 3x + 2 By inspection: g(x) = x^2 + x  1
 one year ago

Studentc14 Group TitleBest ResponseYou've already chosen the best response.0
what's inspection, sorry?
 one year ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
Figuring it out by looking at it
 one year ago

Studentc14 Group TitleBest ResponseYou've already chosen the best response.0
I don't follow, how you get this part? 3(g(x)) + 5 = 3x^2 + 3x + 2
 one year ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
we know h(x) = 3x^2 + 3x +2 > (1) and we know f.g = f(g(x)) but f(x) = 3x + 5, therefore f(g(x)) = 3(g(x)) + 5 > (2) and we know that f.g = h > f(g(x)) = h(x) therefore: (1) = (2) 3(g(x)) + 5 = 3x^2 + 3x +2
 one year ago

Studentc14 Group TitleBest ResponseYou've already chosen the best response.0
ohkay, and then you can kinda just look at it and like guess and check and see that x^2+x1 works for g, right?
 one year ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
Yes. Or you can just solve G like a normal variable: 3(g(x)) + 5 = 3x^2 + 3x +2 Substract 5 on both sides: 3(g(x)) = 3x^2 + 3x 3 Divide by 3: g(x) = x^2 + x  1
 one year ago

Studentc14 Group TitleBest ResponseYou've already chosen the best response.0
oh! that's much clearer. thank you so much!
 one year ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
haha, colloquial for "cool, no problem"
 one year ago
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