A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1f . g = h f = 3x + 5 h = 3x^2 + 3x + 2 so f(g(x)) = 3x^2 + 3x + 2 That means: 3(g(x)) + 5 = 3x^2 + 3x + 2 By inspection: g(x) = x^2 + x  1

Studentc14
 2 years ago
Best ResponseYou've already chosen the best response.0what's inspection, sorry?

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1Figuring it out by looking at it

Studentc14
 2 years ago
Best ResponseYou've already chosen the best response.0I don't follow, how you get this part? 3(g(x)) + 5 = 3x^2 + 3x + 2

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1we know h(x) = 3x^2 + 3x +2 > (1) and we know f.g = f(g(x)) but f(x) = 3x + 5, therefore f(g(x)) = 3(g(x)) + 5 > (2) and we know that f.g = h > f(g(x)) = h(x) therefore: (1) = (2) 3(g(x)) + 5 = 3x^2 + 3x +2

Studentc14
 2 years ago
Best ResponseYou've already chosen the best response.0ohkay, and then you can kinda just look at it and like guess and check and see that x^2+x1 works for g, right?

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1Yes. Or you can just solve G like a normal variable: 3(g(x)) + 5 = 3x^2 + 3x +2 Substract 5 on both sides: 3(g(x)) = 3x^2 + 3x 3 Divide by 3: g(x) = x^2 + x  1

Studentc14
 2 years ago
Best ResponseYou've already chosen the best response.0oh! that's much clearer. thank you so much!

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1haha, colloquial for "cool, no problem"
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.