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simplify (x^-3y^5z^0/x^2y^8)^2

Mathematics
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\[\frac{ x^-3y^5z^0 }{ x^2y^8 }^2\]
()^2
\[(x ^{-3}y ^{5}z ^{0}/x ^{2}y ^{8})^{2}\] simplify it by dividing term by term like x^-3/x^2 =x^-3-2=? y^5/y^3=y^5-3=? also what is z^0=?

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Other answers:

x^6
y^-15
\[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\]
\[\left(\begin{matrix}x^-3y^5z^0 \\ x^2y^8\end{matrix}\right)^2\]
thats the problem
i'm new at this
yeah later on you squared them after simplifying the terms
oh
i'm so lost with these
but first simlipfying the division of powers are adding and subtracting on not multiplying .. :D
so x^1y^-3z^0
\[\frac{ z }{ x^2y^6 }\]
\[\frac{ y ^{-c} }{ y ^{b} }=y ^{-c-b}\]
look i dont understand
\[\frac{ v ^{-c} }{ y ^{b} }=y ^{-c}*y ^{-b}=y ^{-c-b}\]
i get the x^-1*2 y^-3*2
for example only \[\frac{ y ^{-5} }{ y ^{7} }=y ^{-5}*y ^{-7}=y ^{-5-7}=y ^{-12}\]
oh
when you move the denominator to the numerator the sign of its power is change
ok
\[\left(\begin{matrix}x^0 \\ x^1y^3\end{matrix}\right)^2\]
thats what i got
\[\left(\begin{matrix}z \\ x^1y^3\end{matrix}\right)^2\]
that top is z
hm the idea is to move all the denominator upward to the numerator first then do add or subtract
so x^-3-2y^5-8z^0
yes correct and z^0=1 right?
i guess
so x^-1y-3z^1
any number or letter raised to the power of zero is =1
oh right i have been working on homework for the last 5 hours my mind is fried =)
hmm what is -2-3=? 5-8=?
your 5-8= -3 is correct :D
-5
yesss :D
yess =)
so whats the answer now?
so x^-5y^-3x^1
than that times 2
so x^-5*2=-10 y^-3*2=-6 x^1*2=2
\[\left(\begin{matrix}z^2 \\ x^10y^6\end{matrix}\right)\]
now that z^0=1 \[(x ^{-5}y ^{-3})^{2}=\]?
x^-10y^-6
\[(x ^{b})^{a}=x ^{ab}\] multiply now the power here
x^-5*2
=10
yess correct do that to y also
y^-3*2=-6
yess but dont forget about the sign :D
so it's z^2/x^10y^6
hmm z is not supposed to be there any more since its value is 1 anything you multiply by 1 is itself like ax1=a
oh so it's 1/x^10y^6
yesssssssssssss :D
its right!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
thanks
YW have fun now and enjoy solving good luck ......... :D
would u mind helping me with the other one i have on line
ok yesss where is it? @hannalafave
it did not work but i got one for u now 12a^3-3a^2-5a+10/4a+3
ok the easy one to do for this one is by long division can you try that?
yea can u go to link i sent u?
ok

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