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hannalafave

  • 3 years ago

simplify (x^-3y^5z^0/x^2y^8)^2

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  1. hannalafave
    • 3 years ago
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    \[\frac{ x^-3y^5z^0 }{ x^2y^8 }^2\]

  2. hannalafave
    • 3 years ago
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    ()^2

  3. mark_o.
    • 3 years ago
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    \[(x ^{-3}y ^{5}z ^{0}/x ^{2}y ^{8})^{2}\] simplify it by dividing term by term like x^-3/x^2 =x^-3-2=? y^5/y^3=y^5-3=? also what is z^0=?

  4. hannalafave
    • 3 years ago
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    x^6

  5. hannalafave
    • 3 years ago
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    y^-15

  6. mark_o.
    • 3 years ago
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    \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\]

  7. hannalafave
    • 3 years ago
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    \[\left(\begin{matrix}x^-3y^5z^0 \\ x^2y^8\end{matrix}\right)^2\]

  8. hannalafave
    • 3 years ago
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    thats the problem

  9. hannalafave
    • 3 years ago
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    i'm new at this

  10. mark_o.
    • 3 years ago
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    yeah later on you squared them after simplifying the terms

  11. hannalafave
    • 3 years ago
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    oh

  12. hannalafave
    • 3 years ago
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    i'm so lost with these

  13. mark_o.
    • 3 years ago
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    but first simlipfying the division of powers are adding and subtracting on not multiplying .. :D

  14. hannalafave
    • 3 years ago
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    so x^1y^-3z^0

  15. hannalafave
    • 3 years ago
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    \[\frac{ z }{ x^2y^6 }\]

  16. mark_o.
    • 3 years ago
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    \[\frac{ y ^{-c} }{ y ^{b} }=y ^{-c-b}\]

  17. hannalafave
    • 3 years ago
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    look i dont understand

  18. mark_o.
    • 3 years ago
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    \[\frac{ v ^{-c} }{ y ^{b} }=y ^{-c}*y ^{-b}=y ^{-c-b}\]

  19. hannalafave
    • 3 years ago
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    i get the x^-1*2 y^-3*2

  20. mark_o.
    • 3 years ago
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    for example only \[\frac{ y ^{-5} }{ y ^{7} }=y ^{-5}*y ^{-7}=y ^{-5-7}=y ^{-12}\]

  21. hannalafave
    • 3 years ago
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    oh

  22. mark_o.
    • 3 years ago
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    when you move the denominator to the numerator the sign of its power is change

  23. hannalafave
    • 3 years ago
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    ok

  24. hannalafave
    • 3 years ago
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    \[\left(\begin{matrix}x^0 \\ x^1y^3\end{matrix}\right)^2\]

  25. hannalafave
    • 3 years ago
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    thats what i got

  26. hannalafave
    • 3 years ago
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    \[\left(\begin{matrix}z \\ x^1y^3\end{matrix}\right)^2\]

  27. hannalafave
    • 3 years ago
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    that top is z

  28. mark_o.
    • 3 years ago
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    hm the idea is to move all the denominator upward to the numerator first then do add or subtract

  29. hannalafave
    • 3 years ago
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    so x^-3-2y^5-8z^0

  30. mark_o.
    • 3 years ago
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    yes correct and z^0=1 right?

  31. hannalafave
    • 3 years ago
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    i guess

  32. hannalafave
    • 3 years ago
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    so x^-1y-3z^1

  33. mark_o.
    • 3 years ago
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    any number or letter raised to the power of zero is =1

  34. hannalafave
    • 3 years ago
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    oh right i have been working on homework for the last 5 hours my mind is fried =)

  35. mark_o.
    • 3 years ago
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    hmm what is -2-3=? 5-8=?

  36. mark_o.
    • 3 years ago
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    your 5-8= -3 is correct :D

  37. hannalafave
    • 3 years ago
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    -5

  38. mark_o.
    • 3 years ago
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    yesss :D

  39. hannalafave
    • 3 years ago
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    yess =)

  40. mark_o.
    • 3 years ago
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    so whats the answer now?

  41. hannalafave
    • 3 years ago
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    so x^-5y^-3x^1

  42. hannalafave
    • 3 years ago
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    than that times 2

  43. hannalafave
    • 3 years ago
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    so x^-5*2=-10 y^-3*2=-6 x^1*2=2

  44. hannalafave
    • 3 years ago
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    \[\left(\begin{matrix}z^2 \\ x^10y^6\end{matrix}\right)\]

  45. mark_o.
    • 3 years ago
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    now that z^0=1 \[(x ^{-5}y ^{-3})^{2}=\]?

  46. hannalafave
    • 3 years ago
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    x^-10y^-6

  47. mark_o.
    • 3 years ago
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    \[(x ^{b})^{a}=x ^{ab}\] multiply now the power here

  48. hannalafave
    • 3 years ago
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    x^-5*2

  49. hannalafave
    • 3 years ago
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    =10

  50. mark_o.
    • 3 years ago
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    yess correct do that to y also

  51. hannalafave
    • 3 years ago
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    y^-3*2=-6

  52. mark_o.
    • 3 years ago
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    yess but dont forget about the sign :D

  53. hannalafave
    • 3 years ago
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    so it's z^2/x^10y^6

  54. mark_o.
    • 3 years ago
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    hmm z is not supposed to be there any more since its value is 1 anything you multiply by 1 is itself like ax1=a

  55. hannalafave
    • 3 years ago
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    oh so it's 1/x^10y^6

  56. mark_o.
    • 3 years ago
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    yesssssssssssss :D

  57. hannalafave
    • 3 years ago
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    its right!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

  58. hannalafave
    • 3 years ago
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    thanks

  59. mark_o.
    • 3 years ago
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    YW have fun now and enjoy solving good luck ......... :D

  60. hannalafave
    • 3 years ago
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    would u mind helping me with the other one i have on line

  61. mark_o.
    • 3 years ago
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    ok yesss where is it? @hannalafave

  62. hannalafave
    • 3 years ago
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    it did not work but i got one for u now 12a^3-3a^2-5a+10/4a+3

  63. mark_o.
    • 3 years ago
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    ok the easy one to do for this one is by long division can you try that?

  64. hannalafave
    • 3 years ago
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    yea can u go to link i sent u?

  65. mark_o.
    • 3 years ago
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    ok

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