## hannalafave 2 years ago simplify (x^-3y^5z^0/x^2y^8)^2

1. hannalafave

$\frac{ x^-3y^5z^0 }{ x^2y^8 }^2$

2. hannalafave

()^2

3. mark_o.

$(x ^{-3}y ^{5}z ^{0}/x ^{2}y ^{8})^{2}$ simplify it by dividing term by term like x^-3/x^2 =x^-3-2=? y^5/y^3=y^5-3=? also what is z^0=?

4. hannalafave

x^6

5. hannalafave

y^-15

6. mark_o.

$\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}$

7. hannalafave

$\left(\begin{matrix}x^-3y^5z^0 \\ x^2y^8\end{matrix}\right)^2$

8. hannalafave

thats the problem

9. hannalafave

i'm new at this

10. mark_o.

yeah later on you squared them after simplifying the terms

11. hannalafave

oh

12. hannalafave

i'm so lost with these

13. mark_o.

but first simlipfying the division of powers are adding and subtracting on not multiplying .. :D

14. hannalafave

so x^1y^-3z^0

15. hannalafave

$\frac{ z }{ x^2y^6 }$

16. mark_o.

$\frac{ y ^{-c} }{ y ^{b} }=y ^{-c-b}$

17. hannalafave

look i dont understand

18. mark_o.

$\frac{ v ^{-c} }{ y ^{b} }=y ^{-c}*y ^{-b}=y ^{-c-b}$

19. hannalafave

i get the x^-1*2 y^-3*2

20. mark_o.

for example only $\frac{ y ^{-5} }{ y ^{7} }=y ^{-5}*y ^{-7}=y ^{-5-7}=y ^{-12}$

21. hannalafave

oh

22. mark_o.

when you move the denominator to the numerator the sign of its power is change

23. hannalafave

ok

24. hannalafave

$\left(\begin{matrix}x^0 \\ x^1y^3\end{matrix}\right)^2$

25. hannalafave

thats what i got

26. hannalafave

$\left(\begin{matrix}z \\ x^1y^3\end{matrix}\right)^2$

27. hannalafave

that top is z

28. mark_o.

hm the idea is to move all the denominator upward to the numerator first then do add or subtract

29. hannalafave

so x^-3-2y^5-8z^0

30. mark_o.

yes correct and z^0=1 right?

31. hannalafave

i guess

32. hannalafave

so x^-1y-3z^1

33. mark_o.

any number or letter raised to the power of zero is =1

34. hannalafave

oh right i have been working on homework for the last 5 hours my mind is fried =)

35. mark_o.

hmm what is -2-3=? 5-8=?

36. mark_o.

your 5-8= -3 is correct :D

37. hannalafave

-5

38. mark_o.

yesss :D

39. hannalafave

yess =)

40. mark_o.

41. hannalafave

so x^-5y^-3x^1

42. hannalafave

than that times 2

43. hannalafave

so x^-5*2=-10 y^-3*2=-6 x^1*2=2

44. hannalafave

$\left(\begin{matrix}z^2 \\ x^10y^6\end{matrix}\right)$

45. mark_o.

now that z^0=1 $(x ^{-5}y ^{-3})^{2}=$?

46. hannalafave

x^-10y^-6

47. mark_o.

$(x ^{b})^{a}=x ^{ab}$ multiply now the power here

48. hannalafave

x^-5*2

49. hannalafave

=10

50. mark_o.

yess correct do that to y also

51. hannalafave

y^-3*2=-6

52. mark_o.

yess but dont forget about the sign :D

53. hannalafave

so it's z^2/x^10y^6

54. mark_o.

hmm z is not supposed to be there any more since its value is 1 anything you multiply by 1 is itself like ax1=a

55. hannalafave

oh so it's 1/x^10y^6

56. mark_o.

yesssssssssssss :D

57. hannalafave

its right!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

58. hannalafave

thanks

59. mark_o.

YW have fun now and enjoy solving good luck ......... :D

60. hannalafave

would u mind helping me with the other one i have on line

61. mark_o.

ok yesss where is it? @hannalafave

62. hannalafave

it did not work but i got one for u now 12a^3-3a^2-5a+10/4a+3

63. mark_o.

ok the easy one to do for this one is by long division can you try that?

64. hannalafave

yea can u go to link i sent u?

65. mark_o.

ok