anonymous
  • anonymous
simplify (x^-3y^5z^0/x^2y^8)^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\frac{ x^-3y^5z^0 }{ x^2y^8 }^2\]
anonymous
  • anonymous
()^2
anonymous
  • anonymous
\[(x ^{-3}y ^{5}z ^{0}/x ^{2}y ^{8})^{2}\] simplify it by dividing term by term like x^-3/x^2 =x^-3-2=? y^5/y^3=y^5-3=? also what is z^0=?

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More answers

anonymous
  • anonymous
x^6
anonymous
  • anonymous
y^-15
anonymous
  • anonymous
\[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\]
anonymous
  • anonymous
\[\left(\begin{matrix}x^-3y^5z^0 \\ x^2y^8\end{matrix}\right)^2\]
anonymous
  • anonymous
thats the problem
anonymous
  • anonymous
i'm new at this
anonymous
  • anonymous
yeah later on you squared them after simplifying the terms
anonymous
  • anonymous
oh
anonymous
  • anonymous
i'm so lost with these
anonymous
  • anonymous
but first simlipfying the division of powers are adding and subtracting on not multiplying .. :D
anonymous
  • anonymous
so x^1y^-3z^0
anonymous
  • anonymous
\[\frac{ z }{ x^2y^6 }\]
anonymous
  • anonymous
\[\frac{ y ^{-c} }{ y ^{b} }=y ^{-c-b}\]
anonymous
  • anonymous
look i dont understand
anonymous
  • anonymous
\[\frac{ v ^{-c} }{ y ^{b} }=y ^{-c}*y ^{-b}=y ^{-c-b}\]
anonymous
  • anonymous
i get the x^-1*2 y^-3*2
anonymous
  • anonymous
for example only \[\frac{ y ^{-5} }{ y ^{7} }=y ^{-5}*y ^{-7}=y ^{-5-7}=y ^{-12}\]
anonymous
  • anonymous
oh
anonymous
  • anonymous
when you move the denominator to the numerator the sign of its power is change
anonymous
  • anonymous
ok
anonymous
  • anonymous
\[\left(\begin{matrix}x^0 \\ x^1y^3\end{matrix}\right)^2\]
anonymous
  • anonymous
thats what i got
anonymous
  • anonymous
\[\left(\begin{matrix}z \\ x^1y^3\end{matrix}\right)^2\]
anonymous
  • anonymous
that top is z
anonymous
  • anonymous
hm the idea is to move all the denominator upward to the numerator first then do add or subtract
anonymous
  • anonymous
so x^-3-2y^5-8z^0
anonymous
  • anonymous
yes correct and z^0=1 right?
anonymous
  • anonymous
i guess
anonymous
  • anonymous
so x^-1y-3z^1
anonymous
  • anonymous
any number or letter raised to the power of zero is =1
anonymous
  • anonymous
oh right i have been working on homework for the last 5 hours my mind is fried =)
anonymous
  • anonymous
hmm what is -2-3=? 5-8=?
anonymous
  • anonymous
your 5-8= -3 is correct :D
anonymous
  • anonymous
-5
anonymous
  • anonymous
yesss :D
anonymous
  • anonymous
yess =)
anonymous
  • anonymous
so whats the answer now?
anonymous
  • anonymous
so x^-5y^-3x^1
anonymous
  • anonymous
than that times 2
anonymous
  • anonymous
so x^-5*2=-10 y^-3*2=-6 x^1*2=2
anonymous
  • anonymous
\[\left(\begin{matrix}z^2 \\ x^10y^6\end{matrix}\right)\]
anonymous
  • anonymous
now that z^0=1 \[(x ^{-5}y ^{-3})^{2}=\]?
anonymous
  • anonymous
x^-10y^-6
anonymous
  • anonymous
\[(x ^{b})^{a}=x ^{ab}\] multiply now the power here
anonymous
  • anonymous
x^-5*2
anonymous
  • anonymous
=10
anonymous
  • anonymous
yess correct do that to y also
anonymous
  • anonymous
y^-3*2=-6
anonymous
  • anonymous
yess but dont forget about the sign :D
anonymous
  • anonymous
so it's z^2/x^10y^6
anonymous
  • anonymous
hmm z is not supposed to be there any more since its value is 1 anything you multiply by 1 is itself like ax1=a
anonymous
  • anonymous
oh so it's 1/x^10y^6
anonymous
  • anonymous
yesssssssssssss :D
anonymous
  • anonymous
its right!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
anonymous
  • anonymous
thanks
anonymous
  • anonymous
YW have fun now and enjoy solving good luck ......... :D
anonymous
  • anonymous
would u mind helping me with the other one i have on line
anonymous
  • anonymous
ok yesss where is it? @hannalafave
anonymous
  • anonymous
it did not work but i got one for u now 12a^3-3a^2-5a+10/4a+3
anonymous
  • anonymous
ok the easy one to do for this one is by long division can you try that?
anonymous
  • anonymous
yea can u go to link i sent u?
anonymous
  • anonymous
ok

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