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hannalafave

simplify (x^-3y^5z^0/x^2y^8)^2

  • one year ago
  • one year ago

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  1. hannalafave
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    \[\frac{ x^-3y^5z^0 }{ x^2y^8 }^2\]

    • one year ago
  2. hannalafave
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    ()^2

    • one year ago
  3. mark_o.
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    \[(x ^{-3}y ^{5}z ^{0}/x ^{2}y ^{8})^{2}\] simplify it by dividing term by term like x^-3/x^2 =x^-3-2=? y^5/y^3=y^5-3=? also what is z^0=?

    • one year ago
  4. hannalafave
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    x^6

    • one year ago
  5. hannalafave
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    y^-15

    • one year ago
  6. mark_o.
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    \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\]

    • one year ago
  7. hannalafave
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    \[\left(\begin{matrix}x^-3y^5z^0 \\ x^2y^8\end{matrix}\right)^2\]

    • one year ago
  8. hannalafave
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    thats the problem

    • one year ago
  9. hannalafave
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    i'm new at this

    • one year ago
  10. mark_o.
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    yeah later on you squared them after simplifying the terms

    • one year ago
  11. hannalafave
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    oh

    • one year ago
  12. hannalafave
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    i'm so lost with these

    • one year ago
  13. mark_o.
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    but first simlipfying the division of powers are adding and subtracting on not multiplying .. :D

    • one year ago
  14. hannalafave
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    so x^1y^-3z^0

    • one year ago
  15. hannalafave
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    \[\frac{ z }{ x^2y^6 }\]

    • one year ago
  16. mark_o.
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    \[\frac{ y ^{-c} }{ y ^{b} }=y ^{-c-b}\]

    • one year ago
  17. hannalafave
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    look i dont understand

    • one year ago
  18. mark_o.
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    \[\frac{ v ^{-c} }{ y ^{b} }=y ^{-c}*y ^{-b}=y ^{-c-b}\]

    • one year ago
  19. hannalafave
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    i get the x^-1*2 y^-3*2

    • one year ago
  20. mark_o.
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    for example only \[\frac{ y ^{-5} }{ y ^{7} }=y ^{-5}*y ^{-7}=y ^{-5-7}=y ^{-12}\]

    • one year ago
  21. hannalafave
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    oh

    • one year ago
  22. mark_o.
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    when you move the denominator to the numerator the sign of its power is change

    • one year ago
  23. hannalafave
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    ok

    • one year ago
  24. hannalafave
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    \[\left(\begin{matrix}x^0 \\ x^1y^3\end{matrix}\right)^2\]

    • one year ago
  25. hannalafave
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    thats what i got

    • one year ago
  26. hannalafave
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    \[\left(\begin{matrix}z \\ x^1y^3\end{matrix}\right)^2\]

    • one year ago
  27. hannalafave
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    that top is z

    • one year ago
  28. mark_o.
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    hm the idea is to move all the denominator upward to the numerator first then do add or subtract

    • one year ago
  29. hannalafave
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    so x^-3-2y^5-8z^0

    • one year ago
  30. mark_o.
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    yes correct and z^0=1 right?

    • one year ago
  31. hannalafave
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    i guess

    • one year ago
  32. hannalafave
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    so x^-1y-3z^1

    • one year ago
  33. mark_o.
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    any number or letter raised to the power of zero is =1

    • one year ago
  34. hannalafave
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    oh right i have been working on homework for the last 5 hours my mind is fried =)

    • one year ago
  35. mark_o.
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    hmm what is -2-3=? 5-8=?

    • one year ago
  36. mark_o.
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    your 5-8= -3 is correct :D

    • one year ago
  37. hannalafave
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    -5

    • one year ago
  38. mark_o.
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    yesss :D

    • one year ago
  39. hannalafave
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    yess =)

    • one year ago
  40. mark_o.
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    so whats the answer now?

    • one year ago
  41. hannalafave
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    so x^-5y^-3x^1

    • one year ago
  42. hannalafave
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    than that times 2

    • one year ago
  43. hannalafave
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    so x^-5*2=-10 y^-3*2=-6 x^1*2=2

    • one year ago
  44. hannalafave
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    \[\left(\begin{matrix}z^2 \\ x^10y^6\end{matrix}\right)\]

    • one year ago
  45. mark_o.
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    now that z^0=1 \[(x ^{-5}y ^{-3})^{2}=\]?

    • one year ago
  46. hannalafave
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    x^-10y^-6

    • one year ago
  47. mark_o.
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    \[(x ^{b})^{a}=x ^{ab}\] multiply now the power here

    • one year ago
  48. hannalafave
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    x^-5*2

    • one year ago
  49. hannalafave
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    =10

    • one year ago
  50. mark_o.
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    yess correct do that to y also

    • one year ago
  51. hannalafave
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    y^-3*2=-6

    • one year ago
  52. mark_o.
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    yess but dont forget about the sign :D

    • one year ago
  53. hannalafave
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    so it's z^2/x^10y^6

    • one year ago
  54. mark_o.
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    hmm z is not supposed to be there any more since its value is 1 anything you multiply by 1 is itself like ax1=a

    • one year ago
  55. hannalafave
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    oh so it's 1/x^10y^6

    • one year ago
  56. mark_o.
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    yesssssssssssss :D

    • one year ago
  57. hannalafave
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    its right!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

    • one year ago
  58. hannalafave
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    thanks

    • one year ago
  59. mark_o.
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    YW have fun now and enjoy solving good luck ......... :D

    • one year ago
  60. hannalafave
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    would u mind helping me with the other one i have on line

    • one year ago
  61. mark_o.
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    ok yesss where is it? @hannalafave

    • one year ago
  62. hannalafave
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    it did not work but i got one for u now 12a^3-3a^2-5a+10/4a+3

    • one year ago
  63. mark_o.
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    ok the easy one to do for this one is by long division can you try that?

    • one year ago
  64. hannalafave
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    yea can u go to link i sent u?

    • one year ago
  65. mark_o.
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    ok

    • one year ago
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