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hannalafave

  • 3 years ago

12a^3-3a^2-5a+10/4a+3

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  1. hannalafave
    • 3 years ago
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    long division

  2. hannalafave
    • 3 years ago
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    i know u do this first |dw:1354757932663:dw|

  3. hannalafave
    • 3 years ago
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    4a^2-3 divided in to 12a^2-3a^2=3a

  4. mark_o.
    • 3 years ago
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    ok lets do this step by step :D

  5. hannalafave
    • 3 years ago
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    ok

  6. hannalafave
    • 3 years ago
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    \[12a^3-3a^2-5a+10\div4a+3\]

  7. hannalafave
    • 3 years ago
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    3a^5

  8. mark_o.
    • 3 years ago
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    first whats 12a^3/4a ?

  9. hannalafave
    • 3 years ago
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    3a^2

  10. mark_o.
    • 3 years ago
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    yes correct :D now lets do the procedure as we are dividing numbers like in a regular way

  11. hannalafave
    • 3 years ago
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    |dw:1354759034295:dw|

  12. hannalafave
    • 3 years ago
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    yea i know that what it 6 or is it -6

  13. hannalafave
    • 3 years ago
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    ops -6

  14. mark_o.
    • 3 years ago
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    12a^3 -3a^2 -(12 a^3 +9a^2)=0 - 12a2 yes or no?

  15. hannalafave
    • 3 years ago
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    yes

  16. mark_o.
    • 3 years ago
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    ok continue dividing that using the correct answer :D

  17. hannalafave
    • 3 years ago
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    so 12a^2-5a u need to use a 3a again

  18. mark_o.
    • 3 years ago
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    remember always use parenthesis so that you can remember your sign

  19. mark_o.
    • 3 years ago
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    yes correct use -3a

  20. hannalafave
    • 3 years ago
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    (-3a)|dw:1354760013653:dw|

  21. mark_o.
    • 3 years ago
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    - 12x^2 - 5x -( -12x^2 - 9x ) ---------------- 0 + 4x yes or no?

  22. hannalafave
    • 3 years ago
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    yes

  23. mark_o.
    • 3 years ago
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    your -9 became +9 correct? so -5a +9a= 4a

  24. hannalafave
    • 3 years ago
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    yes so we have 4a+10 left

  25. mark_o.
    • 3 years ago
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    yes continue doing division :D

  26. hannalafave
    • 3 years ago
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    1 * 4a+3

  27. mark_o.
    • 3 years ago
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    + 4 a +10 -( 4a + 3 } --------------- 0 + 7=R

  28. hannalafave
    • 3 years ago
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    so the answer is 3a^2-3a+1 7/4a+3

  29. mark_o.
    • 3 years ago
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    yeahhh correct :D

  30. hannalafave
    • 3 years ago
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    it says it's wrong =(

  31. mark_o.
    • 3 years ago
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    you can re chack that by multiplying (4a^2 +3)(3a^2 -3x +1 + 7/(4x+3))

  32. hannalafave
    • 3 years ago
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    its the faction

  33. hannalafave
    • 3 years ago
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    fraction

  34. mark_o.
    • 3 years ago
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    will you pls check the real prob again is this it ? 12a^3-3a^2-5a+10/(4a+3)

  35. hannalafave
    • 3 years ago
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    yea thats it

  36. hannalafave
    • 3 years ago
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    is it -1

  37. mark_o.
    • 3 years ago
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    ok lets try multiplying them to check if we arrived on it

  38. mark_o.
    • 3 years ago
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    (4x+3)(3x^2 -3x +1 + 1/ (4x+3))

  39. hannalafave
    • 3 years ago
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    12a^3-12a^2+4

  40. mark_o.
    • 3 years ago
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    the R=7 therefore (im gonna use x instead of a here) :D (4x+3)(3x^2 -3x +1 + 7/ (4x+3)) =12x^3 +9x^2 -12x^2 - 9x +4x +3 +7 = 12x^3 -3x^2-5x +10 or = 12a^3 -3a^2-5a +10 correct ?

  41. hannalafave
    • 3 years ago
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    the last one is correct

  42. mark_o.
    • 3 years ago
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    ok R=7 maybe thats why its looks like its wrong in the beginning?

  43. hannalafave
    • 3 years ago
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    it need +7/4a+3

  44. mark_o.
    • 3 years ago
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    whats the answer in the book?

  45. mark_o.
    • 3 years ago
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    yes correct

  46. hannalafave
    • 3 years ago
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    ya but i ask it to many time so i got it wrong =(

  47. hannalafave
    • 3 years ago
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    i have till12 tonight to finish these problem i'm at a lot i only need 1.4% to pass this semester

  48. hannalafave
    • 3 years ago
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    the new problem is 9a^3-3a^2-3a+15/3a+2

  49. hannalafave
    • 3 years ago
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    got that one right =)

  50. mark_o.
    • 3 years ago
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    ok on that one whats the first guess?

  51. mark_o.
    • 3 years ago
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    9a^3 / 3a= ?

  52. hannalafave
    • 3 years ago
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    i got it right already i'm on 9b^2-6b-8/3b-1

  53. hannalafave
    • 3 years ago
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    i got so far on this one 3b is the first

  54. mark_o.
    • 3 years ago
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    ok

  55. hannalafave
    • 3 years ago
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    the answer i came up with is 3b-3b- 7/3b-1

  56. mark_o.
    • 3 years ago
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    nope :D

  57. hannalafave
    • 3 years ago
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    no its wrong =(

  58. mark_o.
    • 3 years ago
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    try again.... :D

  59. hannalafave
    • 3 years ago
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    oh 3b-1b-7/3b-1

  60. hannalafave
    • 3 years ago
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    -9/3b-1

  61. mark_o.
    • 3 years ago
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    hmm if your answer start with 3b the next to it must not have any more variable b because the polynomial like ax^5 +b x^4 +cx^3 +dx^2 +ex + f you are here -----> 3b +__? gets?

  62. mark_o.
    • 3 years ago
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    the power should be in ascending or descending order :D

  63. hannalafave
    • 3 years ago
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    thats right just 1

  64. hannalafave
    • 3 years ago
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    descending

  65. mark_o.
    • 3 years ago
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    ok good,, so whats your answer?

  66. hannalafave
    • 3 years ago
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    3b-1- 7/3b-1

  67. mark_o.
    • 3 years ago
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    hmm (3b-1)(3b-1)=?

  68. mark_o.
    • 3 years ago
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    i think you slipped on your R=? re check again on getting your R?

  69. hannalafave
    • 3 years ago
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    9b^2-3b-3b+2=== 9b^2+-6b+2

  70. hannalafave
    • 3 years ago
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    -8-(-1) =-7

  71. mark_o.
    • 3 years ago
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    -3b -8 -(-3b +1) ---------- 0 - ?

  72. hannalafave
    • 3 years ago
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    -9

  73. hannalafave
    • 3 years ago
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    i got it i got it =) thanks again

  74. mark_o.
    • 3 years ago
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    ok YW :D

  75. hannalafave
    • 3 years ago
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    i'm a slow learner and never did this in high school

  76. mark_o.
    • 3 years ago
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    ok now you are doing good.... it just takes practice :D

  77. hannalafave
    • 3 years ago
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    yea thank god this is my last semester in it......

  78. mark_o.
    • 3 years ago
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    no one is a slow learner... its just depend if you are interested to it before or now or then .. :D

  79. hannalafave
    • 3 years ago
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    i'm not i will not use this in my culinary classes at all!!!!!!!!!!!

  80. mark_o.
    • 3 years ago
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    ive seen that you are interested to it so i did show you step by step it doesnt mean you are slow learner.. its because you are now learning it or reviewing it ..............:D

  81. hannalafave
    • 3 years ago
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    can u help me with my last one

  82. mark_o.
    • 3 years ago
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    yes you will in finding the correct ratios of those thing you need to cook according to the recipe :D

  83. hannalafave
    • 3 years ago
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    3-5x^2/x+2

  84. mark_o.
    • 3 years ago
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    ok what is it

  85. hannalafave
    • 3 years ago
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    i know u have to do this -5x^2+0x+3/x+2

  86. mark_o.
    • 3 years ago
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    arrange them first in ascending order then divide

  87. mark_o.
    • 3 years ago
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    yes correct go ahjead and try that

  88. hannalafave
    • 3 years ago
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    ok i came up with -5x-10 -17/x-2

  89. hannalafave
    • 3 years ago
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    ops +10

  90. hannalafave
    • 3 years ago
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    and +17

  91. mark_o.
    • 3 years ago
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    yesssssssssssss correct..............:D

  92. mark_o.
    • 3 years ago
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    hmm not +17 :(

  93. hannalafave
    • 3 years ago
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    yes -5x+10 -17/x-2

  94. hannalafave
    • 3 years ago
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    no it says its wrong =(

  95. mark_o.
    • 3 years ago
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    .this is the correct prob 3-5x^2/x+2 tyhen it should be x+2

  96. mark_o.
    • 3 years ago
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    not x-2

  97. hannalafave
    • 3 years ago
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    it worked =)

  98. mark_o.
    • 3 years ago
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    ok always check the prob correctly thats the main key :D

  99. mark_o.
    • 3 years ago
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    ok good...... :D

  100. mark_o.
    • 3 years ago
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    i can see from now that youl be earning good money in your culinary class after graduating :D

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