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12a^3-3a^2-5a+10/4a+3

Mathematics
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long division
i know u do this first |dw:1354757932663:dw|
4a^2-3 divided in to 12a^2-3a^2=3a

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Other answers:

ok lets do this step by step :D
ok
\[12a^3-3a^2-5a+10\div4a+3\]
3a^5
first whats 12a^3/4a ?
3a^2
yes correct :D now lets do the procedure as we are dividing numbers like in a regular way
|dw:1354759034295:dw|
yea i know that what it 6 or is it -6
ops -6
12a^3 -3a^2 -(12 a^3 +9a^2)=0 - 12a2 yes or no?
yes
ok continue dividing that using the correct answer :D
so 12a^2-5a u need to use a 3a again
remember always use parenthesis so that you can remember your sign
yes correct use -3a
(-3a)|dw:1354760013653:dw|
- 12x^2 - 5x -( -12x^2 - 9x ) ---------------- 0 + 4x yes or no?
yes
your -9 became +9 correct? so -5a +9a= 4a
yes so we have 4a+10 left
yes continue doing division :D
1 * 4a+3
+ 4 a +10 -( 4a + 3 } --------------- 0 + 7=R
so the answer is 3a^2-3a+1 7/4a+3
yeahhh correct :D
it says it's wrong =(
you can re chack that by multiplying (4a^2 +3)(3a^2 -3x +1 + 7/(4x+3))
its the faction
fraction
will you pls check the real prob again is this it ? 12a^3-3a^2-5a+10/(4a+3)
yea thats it
is it -1
ok lets try multiplying them to check if we arrived on it
(4x+3)(3x^2 -3x +1 + 1/ (4x+3))
12a^3-12a^2+4
the R=7 therefore (im gonna use x instead of a here) :D (4x+3)(3x^2 -3x +1 + 7/ (4x+3)) =12x^3 +9x^2 -12x^2 - 9x +4x +3 +7 = 12x^3 -3x^2-5x +10 or = 12a^3 -3a^2-5a +10 correct ?
the last one is correct
ok R=7 maybe thats why its looks like its wrong in the beginning?
it need +7/4a+3
whats the answer in the book?
yes correct
ya but i ask it to many time so i got it wrong =(
i have till12 tonight to finish these problem i'm at a lot i only need 1.4% to pass this semester
the new problem is 9a^3-3a^2-3a+15/3a+2
got that one right =)
ok on that one whats the first guess?
9a^3 / 3a= ?
i got it right already i'm on 9b^2-6b-8/3b-1
i got so far on this one 3b is the first
ok
the answer i came up with is 3b-3b- 7/3b-1
nope :D
no its wrong =(
try again.... :D
oh 3b-1b-7/3b-1
-9/3b-1
hmm if your answer start with 3b the next to it must not have any more variable b because the polynomial like ax^5 +b x^4 +cx^3 +dx^2 +ex + f you are here -----> 3b +__? gets?
the power should be in ascending or descending order :D
thats right just 1
descending
ok good,, so whats your answer?
3b-1- 7/3b-1
hmm (3b-1)(3b-1)=?
i think you slipped on your R=? re check again on getting your R?
9b^2-3b-3b+2=== 9b^2+-6b+2
-8-(-1) =-7
-3b -8 -(-3b +1) ---------- 0 - ?
-9
i got it i got it =) thanks again
ok YW :D
i'm a slow learner and never did this in high school
ok now you are doing good.... it just takes practice :D
yea thank god this is my last semester in it......
no one is a slow learner... its just depend if you are interested to it before or now or then .. :D
i'm not i will not use this in my culinary classes at all!!!!!!!!!!!
ive seen that you are interested to it so i did show you step by step it doesnt mean you are slow learner.. its because you are now learning it or reviewing it ..............:D
can u help me with my last one
yes you will in finding the correct ratios of those thing you need to cook according to the recipe :D
3-5x^2/x+2
ok what is it
i know u have to do this -5x^2+0x+3/x+2
arrange them first in ascending order then divide
yes correct go ahjead and try that
ok i came up with -5x-10 -17/x-2
ops +10
and +17
yesssssssssssss correct..............:D
hmm not +17 :(
yes -5x+10 -17/x-2
no it says its wrong =(
.this is the correct prob 3-5x^2/x+2 tyhen it should be x+2
not x-2
it worked =)
ok always check the prob correctly thats the main key :D
ok good...... :D
i can see from now that youl be earning good money in your culinary class after graduating :D

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