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NickR Group TitleBest ResponseYou've already chosen the best response.0
so (4x3)^2=(4x3)(4x3) right
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
so take that and foil it
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
(4x3)(4x3) = 4x(4x  3)  3(4x  3) = 16x^2  12x  12x +9 = 16x^2  24x + 9
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
16x^224x+24=0
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
but its not = to 0 its =15
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
(4x3)(4x3) = 4x(4x  3)  3(4x  3) = 16x^2  12x  12x +9 = 16x^2  24x + 9
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
my bad see you already did that
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
so now is there a common number that they are all divisible by?
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
wait im at 16x^224x+9=15 right?
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
ya then add the 15 to get 16x^224x+24=0
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
okay yeah i did that
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
now find a common denominator
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
so does that then turn into 2x^23x=3=0?
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
2x^23x+3 sorry
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
16x^224x+9=15 16x^2  24x + 24 = 0 8(2x^2  3x + 3) = 0 2x^2  3x + 3 = 0 x^2  3/2 + 3/2 = 0 x^2  3/2x = 3/2 x^2 3/2x + 9/16 = 3/2 + 9/16 (x  3/4)^2 = 15/16 Solution is imaginary
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
then what do i do?
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
the answer is 3 + or  the square root of 15 divided by4 but idk how to get it
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
i would do the quadratic formula
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
b + or  the square root of b^2 4ac divided by 2a?
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{b \pm \sqrt{b^2  4ac}}{2a}\]
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
(b+sqrt(b^24ac))/2a
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
i got it thanks to both of you!
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
not a problem
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
You got what? Mind sharing what you got?
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
3 + or  the square root of 15 divided by 4
 2 years ago

KG1234 Group TitleBest ResponseYou've already chosen the best response.0
3+ or  i square root 15 divided by 4 sorry i forgot the "i"
 2 years ago
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