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inkyvoydBest ResponseYou've already chosen the best response.0
Well, what's the first derivative?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
use the product rule...
 one year ago

IdealistBest ResponseYou've already chosen the best response.0
The first derivative is (cosx)^2(sinx)^2. But how do I take the derivative of that?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
well, remember that cos(a+b)=cos a cos bsin a sin b...
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
in other words, use the double angle formula for to reduce the following expression you have obtained. And then use the chain rule.
 one year ago

SujayBest ResponseYou've already chosen the best response.2
\[f'(x)=cosx(\cos(x))+(\sin(x)\sin(x))\] Product Rule and Derivatives of Trigs Simplify. \[f'(x)=\cos ^{2}x\sin ^{2}x\] \[f''(x)=2\cos(x)(\sin(x))2\sin(x)(\cos(x))\] Derivative of Trig and Chain Rule
 one year ago

hcmathkimBest ResponseYou've already chosen the best response.0
bring the power down, keep the inside, differentiate inside
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
Since no one seems to get it USE COS^2 XSIN^2 X=COS(2x) TO SIMPLIFY EXPRESSION
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
simplified expression is dy/dx=cos(2x) then take the dervative of that
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
@Idealist are you followign?
 one year ago

IdealistBest ResponseYou've already chosen the best response.0
Yes. I got it. Thanks for the help, guys.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
I like medals. LOL but yeah, nice to see :) let me know your final answer so I can check it
 one year ago
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