A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2start with \[2x^28x+7=0\] then use \[x=\frac{b\pm\sqrt{b^24ac}}{2a}\] with \(a=2,b=8,c=7\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2second step is \[x=\frac{8\pm\sqrt{8^24\times 2\times 7}}{2\times 2}\] then a bunch of arithmetic

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2oh ok we compute \[\frac{8\pm\sqrt{6456}}{4}\] \[=\frac{8\pm\sqrt{8}}{4}\] \[=\frac{8\pm2\sqrt{2}}{4}\] \[=\frac{2(4+\sqrt{2})}{4}\] \[=\frac{4+\sqrt{2}}{2}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2rewrite \(\sqrt{8}\) as \(2\sqrt{2}\) then factor and cancel details are above

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2it is because \(\sqrt{8}=\sqrt{4\times 2}=\sqrt{4}\sqrt{2}=2\sqrt{2}\) in simplest radical form

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2then be careful with factoring before you cancel the common factor of 2 top and bottom

candyme
 2 years ago
Best ResponseYou've already chosen the best response.0Ok, you're going to multiply the terms in the radical\[x=\frac{8 \pm \sqrt{6456}}{4}\]\[x= \frac{8 \pm \sqrt{8}}{4}\]\[x=\frac{8 \pm \sqrt{2*4}}{4}\]The 4 comes out as a 2 since the square root of 4 is 2\[x= \frac{8 \pm 2\sqrt{2}}{4}\]Divide by 2\[x=\frac{4 \pm \sqrt{2}}{2}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2it could be written as \[2\pm\frac{\sqrt{2}}{2}\]

candyme
 2 years ago
Best ResponseYou've already chosen the best response.0Satellite is right, I was about to say that :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.