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natasha.aries

  • 2 years ago

A 0.25 Kg hockey puck is hit with a force of 7.00 N. The force of friction acting on the puck when it is hit is 0.30 N. What is the magnitude of the acceleration of the hockey puck? A 12.7 m/s2 B 28.0 m/s2 C 26.8 m/s2 D 29.2 m/s2

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  1. qvbsinteta
    • 2 years ago
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    C is the answer. just find the net force by subtracting 7-0.3 and dividing by acceleration

  2. natasha.aries
    • 2 years ago
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    i dont understand what it means by magnitude of acceleration

  3. qvbsinteta
    • 2 years ago
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    it just means size

  4. natasha.aries
    • 2 years ago
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    what would the acceleration be in this case? would be have to solve for it?

  5. qvbsinteta
    • 2 years ago
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    F net= massxacceleration

  6. VeritasVosLiberabit
    • 2 years ago
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    \[F _{1}-F _{2}=ma\] you solve for a by dividing by the mass. F1 is 7 and F2 is .3

  7. cesckay
    • 2 years ago
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    force - friction = mass x acceleration 7.0N - 0.3N= 0.25 x a 6.7/0.25 = a a=26.8m/s2

  8. VeritasVosLiberabit
    • 2 years ago
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    This is simply an instantaneous acceleration for the puck at this given moment in time.

  9. natasha.aries
    • 2 years ago
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    thanks yall! sorry i wish i couldve given you all the best answer!

  10. qvbsinteta
    • 2 years ago
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    i just noticed the typo in my first post, its divide by mass

  11. natasha.aries
    • 2 years ago
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    yeah thats why i was confused @qvbsinteta haha

  12. cesckay
    • 2 years ago
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    F=ma magnitude of the acceleration just means that the acceleration is in the direction of the applied force and it cannot be zero (0). so just keep in mind that magnitude is the same as the size.

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