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natasha.aries Group Title

A 0.25 Kg hockey puck is hit with a force of 7.00 N. The force of friction acting on the puck when it is hit is 0.30 N. What is the magnitude of the acceleration of the hockey puck? A 12.7 m/s2 B 28.0 m/s2 C 26.8 m/s2 D 29.2 m/s2

  • one year ago
  • one year ago

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  1. qvbsinteta Group Title
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    C is the answer. just find the net force by subtracting 7-0.3 and dividing by acceleration

    • one year ago
  2. natasha.aries Group Title
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    i dont understand what it means by magnitude of acceleration

    • one year ago
  3. qvbsinteta Group Title
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    it just means size

    • one year ago
  4. natasha.aries Group Title
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    what would the acceleration be in this case? would be have to solve for it?

    • one year ago
  5. qvbsinteta Group Title
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    F net= massxacceleration

    • one year ago
  6. VeritasVosLiberabit Group Title
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    \[F _{1}-F _{2}=ma\] you solve for a by dividing by the mass. F1 is 7 and F2 is .3

    • one year ago
  7. cesckay Group Title
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    force - friction = mass x acceleration 7.0N - 0.3N= 0.25 x a 6.7/0.25 = a a=26.8m/s2

    • one year ago
  8. VeritasVosLiberabit Group Title
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    This is simply an instantaneous acceleration for the puck at this given moment in time.

    • one year ago
  9. natasha.aries Group Title
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    thanks yall! sorry i wish i couldve given you all the best answer!

    • one year ago
  10. qvbsinteta Group Title
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    i just noticed the typo in my first post, its divide by mass

    • one year ago
  11. natasha.aries Group Title
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    yeah thats why i was confused @qvbsinteta haha

    • one year ago
  12. cesckay Group Title
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    F=ma magnitude of the acceleration just means that the acceleration is in the direction of the applied force and it cannot be zero (0). so just keep in mind that magnitude is the same as the size.

    • one year ago
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