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C is the answer. just find the net force by subtracting 7-0.3 and dividing by acceleration

i dont understand what it means by magnitude of acceleration

it just means size

what would the acceleration be in this case? would be have to solve for it?

F net= massxacceleration

\[F _{1}-F _{2}=ma\] you solve for a by dividing by the mass.
F1 is 7 and F2 is .3

force - friction = mass x acceleration
7.0N - 0.3N= 0.25 x a
6.7/0.25 = a
a=26.8m/s2

This is simply an instantaneous acceleration for the puck at this given moment in time.

thanks yall! sorry i wish i couldve given you all the best answer!

i just noticed the typo in my first post, its divide by mass

yeah thats why i was confused @qvbsinteta haha