anonymous
  • anonymous
A 0.25 Kg hockey puck is hit with a force of 7.00 N. The force of friction acting on the puck when it is hit is 0.30 N. What is the magnitude of the acceleration of the hockey puck? A 12.7 m/s2 B 28.0 m/s2 C 26.8 m/s2 D 29.2 m/s2
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
C is the answer. just find the net force by subtracting 7-0.3 and dividing by acceleration
anonymous
  • anonymous
i dont understand what it means by magnitude of acceleration
anonymous
  • anonymous
it just means size

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anonymous
  • anonymous
what would the acceleration be in this case? would be have to solve for it?
anonymous
  • anonymous
F net= massxacceleration
anonymous
  • anonymous
\[F _{1}-F _{2}=ma\] you solve for a by dividing by the mass. F1 is 7 and F2 is .3
anonymous
  • anonymous
force - friction = mass x acceleration 7.0N - 0.3N= 0.25 x a 6.7/0.25 = a a=26.8m/s2
anonymous
  • anonymous
This is simply an instantaneous acceleration for the puck at this given moment in time.
anonymous
  • anonymous
thanks yall! sorry i wish i couldve given you all the best answer!
anonymous
  • anonymous
i just noticed the typo in my first post, its divide by mass
anonymous
  • anonymous
yeah thats why i was confused @qvbsinteta haha
anonymous
  • anonymous
F=ma magnitude of the acceleration just means that the acceleration is in the direction of the applied force and it cannot be zero (0). so just keep in mind that magnitude is the same as the size.

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