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natasha.aries

  • 2 years ago

A student tosses a 2 kg ball into the air 4 meters above his hand. Ignoring air friction, what will be the magnitude of the velocity of the ball when it returns to his hand? A 1 m/s B 2 m/s C 8 m/s D 10 m/s

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  1. VeritasVosLiberabit
    • 2 years ago
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    \[v _{f}^{2}=v _{i}^{2}+2a \Delta x\]

  2. natasha.aries
    • 2 years ago
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    but you dont have any velocity

  3. VeritasVosLiberabit
    • 2 years ago
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    hmm but actually I'm getting 8.85 as my answer

  4. natasha.aries
    • 2 years ago
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    would vf be 0?

  5. cesckay
    • 2 years ago
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    mgh=0.5mv^2

  6. cesckay
    • 2 years ago
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    potential energy = kinetic energy

  7. natasha.aries
    • 2 years ago
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    hmm ill try both equations!

  8. cesckay
    • 2 years ago
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    ans= 8.85

  9. VeritasVosLiberabit
    • 2 years ago
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    they give the same answer so I think something is missing.

  10. natasha.aries
    • 2 years ago
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    wait so it doesnt matter which equation?

  11. VeritasVosLiberabit
    • 2 years ago
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    no both give the same result.

  12. VeritasVosLiberabit
    • 2 years ago
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    but Im not sure if the answer is correct since 9 isn't listed.

  13. natasha.aries
    • 2 years ago
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    okay would vf = 0 in @VeritasVosLiberabit

  14. VeritasVosLiberabit
    • 2 years ago
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    vi = 0 you are trying to find vf

  15. natasha.aries
    • 2 years ago
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    the answer is supposed to be 8 so i guess thats close right?

  16. natasha.aries
    • 2 years ago
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    oh hah yeah my bad

  17. VeritasVosLiberabit
    • 2 years ago
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    hmm but you dont round downward

  18. VeritasVosLiberabit
    • 2 years ago
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    if it asks for 1 sigfig the answer should be 9.

  19. natasha.aries
    • 2 years ago
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    yeah im a little iffy about that but i can try asking my teacher that one tomorrow morning!

  20. cesckay
    • 2 years ago
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    either way the question might be wrong taking g= 9.81... my best answer could be 10 :)

  21. natasha.aries
    • 2 years ago
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    thanks you guys! ill ask my teacher to verify it

  22. VeritasVosLiberabit
    • 2 years ago
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    you're welcome.

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