## Idealist Group Title If f(-2)=4 and f'(-2)=-1, find the derivative of f(x)/x^2 at x=-2. one year ago one year ago

$g(x)=\frac{f(x)}{x^2}$ $g'(x)=\frac{x^2f'(x)-2xf(x)}{x^4}$ by the quotient rule, fill in the numbers