A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s?
A 51 m
B 8.6 m
C 60 m
D 45 m
anonymous
 4 years ago
The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s? A 51 m B 8.6 m C 60 m D 45 m

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0best answer could be 8.6m

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what formula did u use?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use conservation of energy and solve for mgh=0.5mv^2; expression is h= v^2/(2g)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so u dont need to use the mass at all?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the masses cancel out eventually..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in all cases when dealing with energy, and asking for the height, or in this one specifically?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mgh=0.5mv^2 it is a general expression for the height when u r using the principle of conservation of energy. potential energy equals change in kinetic energy. therefore we get an equation for the height h= V^2/ 2g

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh so it would most probably always cross out! ahh thank you!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.