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natasha.aries

  • 3 years ago

The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s? A 51 m B 8.6 m C 60 m D 45 m

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  1. cesckay
    • 3 years ago
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    best answer could be 8.6m

  2. natasha.aries
    • 3 years ago
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    what formula did u use?

  3. cesckay
    • 3 years ago
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    use conservation of energy and solve for mgh=0.5mv^2; expression is h= v^2/(2g)

  4. natasha.aries
    • 3 years ago
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    so u dont need to use the mass at all?

  5. cesckay
    • 3 years ago
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    the masses cancel out eventually..

  6. natasha.aries
    • 3 years ago
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    how so?

  7. natasha.aries
    • 3 years ago
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    in all cases when dealing with energy, and asking for the height, or in this one specifically?

  8. cesckay
    • 3 years ago
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    mgh=0.5mv^2 it is a general expression for the height when u r using the principle of conservation of energy. potential energy equals change in kinetic energy. therefore we get an equation for the height h= V^2/ 2g

  9. natasha.aries
    • 3 years ago
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    oh so it would most probably always cross out! ahh thank you!

  10. cesckay
    • 3 years ago
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    yup.. :) u welcome

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