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anonymous
 3 years ago
The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s?
A 51 m
B 8.6 m
C 60 m
D 45 m
anonymous
 3 years ago
The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s? A 51 m B 8.6 m C 60 m D 45 m

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0best answer could be 8.6m

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what formula did u use?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use conservation of energy and solve for mgh=0.5mv^2; expression is h= v^2/(2g)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so u dont need to use the mass at all?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the masses cancel out eventually..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0in all cases when dealing with energy, and asking for the height, or in this one specifically?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0mgh=0.5mv^2 it is a general expression for the height when u r using the principle of conservation of energy. potential energy equals change in kinetic energy. therefore we get an equation for the height h= V^2/ 2g

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh so it would most probably always cross out! ahh thank you!
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