Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

natasha.aries Group Title

The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s? A 51 m B 8.6 m C 60 m D 45 m

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. cesckay Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    best answer could be 8.6m

    • 2 years ago
  2. natasha.aries Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    what formula did u use?

    • 2 years ago
  3. cesckay Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    use conservation of energy and solve for mgh=0.5mv^2; expression is h= v^2/(2g)

    • 2 years ago
  4. natasha.aries Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so u dont need to use the mass at all?

    • 2 years ago
  5. cesckay Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    the masses cancel out eventually..

    • 2 years ago
  6. natasha.aries Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    how so?

    • 2 years ago
  7. natasha.aries Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    in all cases when dealing with energy, and asking for the height, or in this one specifically?

    • 2 years ago
  8. cesckay Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    mgh=0.5mv^2 it is a general expression for the height when u r using the principle of conservation of energy. potential energy equals change in kinetic energy. therefore we get an equation for the height h= V^2/ 2g

    • 2 years ago
  9. natasha.aries Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    oh so it would most probably always cross out! ahh thank you!

    • 2 years ago
  10. cesckay Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yup.. :) u welcome

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.