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The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s?
A 51 m
B 8.6 m
C 60 m
D 45 m
 one year ago
 one year ago
The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s? A 51 m B 8.6 m C 60 m D 45 m
 one year ago
 one year ago

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cesckayBest ResponseYou've already chosen the best response.1
best answer could be 8.6m
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
what formula did u use?
 one year ago

cesckayBest ResponseYou've already chosen the best response.1
use conservation of energy and solve for mgh=0.5mv^2; expression is h= v^2/(2g)
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
so u dont need to use the mass at all?
 one year ago

cesckayBest ResponseYou've already chosen the best response.1
the masses cancel out eventually..
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
in all cases when dealing with energy, and asking for the height, or in this one specifically?
 one year ago

cesckayBest ResponseYou've already chosen the best response.1
mgh=0.5mv^2 it is a general expression for the height when u r using the principle of conservation of energy. potential energy equals change in kinetic energy. therefore we get an equation for the height h= V^2/ 2g
 one year ago

natasha.ariesBest ResponseYou've already chosen the best response.0
oh so it would most probably always cross out! ahh thank you!
 one year ago
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