anonymous
  • anonymous
The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s? A 51 m B 8.6 m C 60 m D 45 m
Physics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
best answer could be 8.6m
anonymous
  • anonymous
what formula did u use?
anonymous
  • anonymous
use conservation of energy and solve for mgh=0.5mv^2; expression is h= v^2/(2g)

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anonymous
  • anonymous
so u dont need to use the mass at all?
anonymous
  • anonymous
the masses cancel out eventually..
anonymous
  • anonymous
how so?
anonymous
  • anonymous
in all cases when dealing with energy, and asking for the height, or in this one specifically?
anonymous
  • anonymous
mgh=0.5mv^2 it is a general expression for the height when u r using the principle of conservation of energy. potential energy equals change in kinetic energy. therefore we get an equation for the height h= V^2/ 2g
anonymous
  • anonymous
oh so it would most probably always cross out! ahh thank you!
anonymous
  • anonymous
yup.. :) u welcome

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