anonymous
  • anonymous
The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s? A 51 m B 8.6 m C 60 m D 45 m
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
best answer could be 8.6m
anonymous
  • anonymous
what formula did u use?
anonymous
  • anonymous
use conservation of energy and solve for mgh=0.5mv^2; expression is h= v^2/(2g)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so u dont need to use the mass at all?
anonymous
  • anonymous
the masses cancel out eventually..
anonymous
  • anonymous
how so?
anonymous
  • anonymous
in all cases when dealing with energy, and asking for the height, or in this one specifically?
anonymous
  • anonymous
mgh=0.5mv^2 it is a general expression for the height when u r using the principle of conservation of energy. potential energy equals change in kinetic energy. therefore we get an equation for the height h= V^2/ 2g
anonymous
  • anonymous
oh so it would most probably always cross out! ahh thank you!
anonymous
  • anonymous
yup.. :) u welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.