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- anonymous

The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s?
A 51 m
B 8.6 m
C 60 m
D 45 m

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- anonymous

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- anonymous

best answer could be 8.6m

- anonymous

what formula did u use?

- anonymous

use conservation of energy and solve for
mgh=0.5mv^2; expression is
h= v^2/(2g)

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- anonymous

so u dont need to use the mass at all?

- anonymous

the masses cancel out eventually..

- anonymous

how so?

- anonymous

in all cases when dealing with energy, and asking for the height, or in this one specifically?

- anonymous

mgh=0.5mv^2
it is a general expression for the height when u r using the principle of conservation of energy. potential energy equals change in kinetic energy. therefore we get an equation for the height h= V^2/ 2g

- anonymous

oh so it would most probably always cross out! ahh thank you!

- anonymous

yup.. :) u welcome

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