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jasonxxBest ResponseYou've already chosen the best response.0
\[\tan 3 \theta= 3 *(\frac{ 3 \tan \theta \tan^3 \theta }{ 1 3 \tan^2 \theta }\])
 one year ago

jasonxxBest ResponseYou've already chosen the best response.0
\[9 \tan \theta 3 \tan^3 \theta=\tan^2 \theta3 \tan^3 \theta\] so final equation becomes \[\tan^2 \theta 9 \tan \theta=0\] lets say tan theta=x \[x^29x=0\] solve for x put x=tan theta and get yor answer
 one year ago
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