## neahchristine Solve the equation 3 tan3θ = tan θ one year ago one year ago

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1. jasonxx

$\tan 3 \theta= 3 *(\frac{ 3 \tan \theta- \tan^3 \theta }{ 1- 3 \tan^2 \theta }$)

2. jasonxx

$9 \tan \theta- 3 \tan^3 \theta=\tan^2 \theta-3 \tan^3 \theta$ so final equation becomes $\tan^2 \theta- 9 \tan \theta=0$ lets say tan theta=x $x^2-9x=0$ solve for x put x=tan theta and get yor answer