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neahchristine

  • 3 years ago

Solve the equation 3 tan3θ = tan θ

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  1. jasonxx
    • 3 years ago
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    \[\tan 3 \theta= 3 *(\frac{ 3 \tan \theta- \tan^3 \theta }{ 1- 3 \tan^2 \theta }\])

  2. jasonxx
    • 3 years ago
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    \[9 \tan \theta- 3 \tan^3 \theta=\tan^2 \theta-3 \tan^3 \theta\] so final equation becomes \[\tan^2 \theta- 9 \tan \theta=0\] lets say tan theta=x \[x^2-9x=0\] solve for x put x=tan theta and get yor answer

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