A boulder is launched from the ground by a catapult with a vertical velocity of 13.0 m/s and a horizontal velocity of 15.0 m/s. It misses the enemy castle and hits the ground. How long did it take the boulder to hit enemy ground? (ignore air friction)
A 0.38 s
B 2.65 s
C 0.75 s
D 1.33 s
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
step by step.. find the initial speed of the boulder which is just the resultant component of both forces using Pythagoras theorem.
Not the answer you are looking for? Search for more explanations.
lol.. answer is B.. you dont have to find the resultant component since theres no angle.. sorry :( if you have the vertical component of the velocity, then just use********* time= 2v/g its kind of a long derivation though.. U r supposed to get 2.6503
how do u know u dont use 15?
it is not travelling horizontally right? so the components are independent of each other.. ig you were to plug in the value for the horizontal component, then the answer would be wrong.. the resultant velocity will give you a larger answer..