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natasha.aries

  • 2 years ago

A boulder is launched from the ground by a catapult with a vertical velocity of 13.0 m/s and a horizontal velocity of 15.0 m/s. It misses the enemy castle and hits the ground. How long did it take the boulder to hit enemy ground? (ignore air friction) A 0.38 s B 2.65 s C 0.75 s D 1.33 s

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  1. cesckay
    • 2 years ago
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    step by step.. find the initial speed of the boulder which is just the resultant component of both forces using Pythagoras theorem.

  2. natasha.aries
    • 2 years ago
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    wait so how would u do that?

  3. cesckay
    • 2 years ago
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    X= sqrt(13^2 + 15^2)

  4. natasha.aries
    • 2 years ago
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    and then?

  5. cesckay
    • 2 years ago
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    lol.. answer is B.. you dont have to find the resultant component since theres no angle.. sorry :( if you have the vertical component of the velocity, then just use********* time= 2v/g its kind of a long derivation though.. U r supposed to get 2.6503

  6. cesckay
    • 2 years ago
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    where v=13

  7. natasha.aries
    • 2 years ago
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    how do u know u dont use 15?

  8. cesckay
    • 2 years ago
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    it is not travelling horizontally right? so the components are independent of each other.. ig you were to plug in the value for the horizontal component, then the answer would be wrong.. the resultant velocity will give you a larger answer..

  9. natasha.aries
    • 2 years ago
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    oh okay that makes sense! thanks!

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