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slaaibakBest ResponseYou've already chosen the best response.0
\[\int\limits_{0}^{2\pi}\int\limits_{0}^{\sqrt{7 \over 2}} [5  (7  2x^2  2y^2)] rdrd \theta \]
 one year ago

lynnnBest ResponseYou've already chosen the best response.0
can't get the right answer. what is it supposed to be:)?
 one year ago

slaaibakBest ResponseYou've already chosen the best response.0
sorry, I forgot something \[\int\limits_{0}^{spi}\int\limits_{0}^{\sqrt{ 7\over2}} {[5  (7  2r)]} rdrd \theta\]
 one year ago

slaaibakBest ResponseYou've already chosen the best response.0
Well, if you can't get the right answer, you obviously must know the right answer, and would not be asking for the right answer. Sorry, but I'm not going to evaluate the integral for you. That's the easy part.
 one year ago

slaaibakBest ResponseYou've already chosen the best response.0
There must be a 2pi in the outer integral top bound.
 one year ago

lynnnBest ResponseYou've already chosen the best response.0
I do not know what the answer is.
 one year ago

slaaibakBest ResponseYou've already chosen the best response.0
Then how can you say "can't get the right answer." ?
 one year ago

lynnnBest ResponseYou've already chosen the best response.0
because the answer choices are 2pi, 3pi/2, pi/2, pi, and 5pi/2. and i'm not getting one of these.
 one year ago

slaaibakBest ResponseYou've already chosen the best response.0
I'm suddenly very confused as to what the question asks. Must you get the volum of the area enclosed by the parabaloid and plane? Where does a cylinder come in?
 one year ago

lynnnBest ResponseYou've already chosen the best response.0
yeah i don't understand the question. the hint thats supposed to help me just made me confused even more
 one year ago

slaaibakBest ResponseYou've already chosen the best response.0
Nah I unfortunately don't know what they want, sorry.
 one year ago
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