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slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2\pi}\int\limits_{0}^{\sqrt{7 \over 2}} [5  (7  2x^2  2y^2)] rdrd \theta \]

lynnn
 2 years ago
Best ResponseYou've already chosen the best response.0can't get the right answer. what is it supposed to be:)?

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.0sorry, I forgot something \[\int\limits_{0}^{spi}\int\limits_{0}^{\sqrt{ 7\over2}} {[5  (7  2r)]} rdrd \theta\]

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.0Well, if you can't get the right answer, you obviously must know the right answer, and would not be asking for the right answer. Sorry, but I'm not going to evaluate the integral for you. That's the easy part.

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.0There must be a 2pi in the outer integral top bound.

lynnn
 2 years ago
Best ResponseYou've already chosen the best response.0I do not know what the answer is.

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.0Then how can you say "can't get the right answer." ?

lynnn
 2 years ago
Best ResponseYou've already chosen the best response.0because the answer choices are 2pi, 3pi/2, pi/2, pi, and 5pi/2. and i'm not getting one of these.

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.0I'm suddenly very confused as to what the question asks. Must you get the volum of the area enclosed by the parabaloid and plane? Where does a cylinder come in?

lynnn
 2 years ago
Best ResponseYou've already chosen the best response.0yeah i don't understand the question. the hint thats supposed to help me just made me confused even more

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.0Nah I unfortunately don't know what they want, sorry.
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