anonymous 3 years ago Calc 3! need help!

1. anonymous

2. slaaibak

$\int\limits_{0}^{2\pi}\int\limits_{0}^{\sqrt{7 \over 2}} [5 - (7 - 2x^2 - 2y^2)] rdrd \theta$

3. anonymous

can't get the right answer. what is it supposed to be:)?

4. slaaibak

sorry, I forgot something $\int\limits_{0}^{spi}\int\limits_{0}^{\sqrt{ 7\over2}} {[5 - (7 - 2r)]} rdrd \theta$

5. slaaibak

Well, if you can't get the right answer, you obviously must know the right answer, and would not be asking for the right answer. Sorry, but I'm not going to evaluate the integral for you. That's the easy part.

6. slaaibak

There must be a 2pi in the outer integral top bound.

7. anonymous

I do not know what the answer is.

8. slaaibak

Then how can you say "can't get the right answer." ?

9. anonymous

because the answer choices are 2pi, 3pi/2, pi/2, pi, and 5pi/2. and i'm not getting one of these.

10. slaaibak

I'm suddenly very confused as to what the question asks. Must you get the volum of the area enclosed by the parabaloid and plane? Where does a cylinder come in?

11. anonymous

yeah i don't understand the question. the hint thats supposed to help me just made me confused even more

12. slaaibak

Nah I unfortunately don't know what they want, sorry.