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Raja99Best ResponseYou've already chosen the best response.0
u need to multiply each element of a row with the determinant of the 3x3 matrix
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.3
\[A=\left\begin{array}{ccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\a_{2,1}&a_{2,2}&a_{2,3}&a_{2,4}\\a_{3,1}&a_{3,2}&a_{3,3}&a_{3,4}\\a_{4,1}&a_{4,2}&a_{4,3}&a_{4,4}\end{array}\right\] \[\quad=a_{1,1}\left\begin{array}{ccc}\\a_{2,2}&a_{2,3}&a_{2,4}\\a_{3,2}&a_{3,3}&a_{3,4}\\a_{4,2}&a_{4,3}&a_{4,4}\end{array}\righta_{1,2}\left\begin{array}{ccc}\\a_{2,1}&a_{2,3}&a_{2,4}\\a_{3,1}&a_{3,3}&a_{3,4}\\a_{4,1}&a_{4,3}&a_{4,4}\end{array}\right\]\[\qquad\qquad\qquad+a_{1,3}\left\begin{array}{ccc}\\a_{2,1}&a_{2,2}&a_{2,4}\\a_{3,1}&a_{3,2}&a_{3,4}\\a_{4,1}&a_{4,2}&a_{4,4}\end{array}\righta_{1,4}\left\begin{array}{ccc}\\a_{2,1}&a_{2,2}&a_{2,3}\\a_{3,1}&a_{3,2}&a_{3,3}\\a_{4,1}&a_{4,2}&a_{4,3}\end{array}\right\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.3
that was a lots of typing
 one year ago

Sportaholic013Best ResponseYou've already chosen the best response.0
Thanks a million that's great :D
 one year ago

Sportaholic013Best ResponseYou've already chosen the best response.0
Are the signs also important? ie. +  +  :)
 one year ago

Raja99Best ResponseYou've already chosen the best response.0
very imp.. if not the result ll change a lot
 one year ago

Sportaholic013Best ResponseYou've already chosen the best response.0
Thank you, and do I multipy the diagonal terms and subtract to get a single figure?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.3
\[B=\left\begin{array}{ccc}b_{1,1}&b_{1,2}&b_{1,3}\\b_{2,1}&b_{2,2}&b_{2,3}\\b_{3,1}&b_{3,2}&b_{3,3}\end{array}\right\]\[\qquad =b_{1,1}\left\begin{array}{ccc}b_{2,2}&b_{2,3}\\b_{3,2}&b_{3,3}\end{array}\rightb_{1,2}\left\begin{array}{ccc}b_{2,1}&b_{2,3}\\b_{3,1}&b_{3,3}\end{array}\right+b_{1,3}\left\begin{array}{ccc}b_{2,1}&b_{2,2}\\b_{3,1}&b_{3,2}\end{array}\right\] \[C=\left\begin{array}{ccc}c_{1,1}&c_{1,2}\\c_{2,1}&c_{2,2}\end{array}\right\]\[\qquad=c_{1,1}c_{2,2}c_{1,2}c_{2,1}\]
 one year ago

Sportaholic013Best ResponseYou've already chosen the best response.0
Thank you I understand it now :)
 one year ago
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