anonymous
  • anonymous
Plz help! super challenging question... Evaluate: lim n->inf 1/n[(1/n)^9+(2/n)^9+(3/n)^9+...+(n/n)^9] p.s: i got 0...but i don't think that's right ...
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

UnkleRhaukus
  • UnkleRhaukus
\[\lim\limits_{n\rightarrow\infty} \frac1n\left[\left(\frac1n\right)^9+\left(\frac2n\right)^9+\left(\frac3n\right)^9+...+\left(\frac nn\right)^9\right] \]
anonymous
  • anonymous
yes! it's not 0 is it...
UnkleRhaukus
  • UnkleRhaukus
well the last term looks like it will be one

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

sirm3d
  • sirm3d
1/10 is my answer. is it among the choices?
anonymous
  • anonymous
i separated (1)^9/(n)^9 and factored out all the (n)^9. resulting in (1/n^10) in the front. so that (1/n^10) times (n)^9 the last term will cancel. which will b left with (1/n) and (1/inf) is 0. 0 times anything left in the [ ...] will be 0. right?
anonymous
  • anonymous
how did you get 1/10????
sirm3d
  • sirm3d
\[\large \int\limits_{a}^{b}f(x) dx=\lim_{n \rightarrow +\infty}\sum_{i=1}^{n} f(a+i \Delta x)\Delta x,\quad \Delta x = \frac{ b-a }{ n }\]
anonymous
  • anonymous
i has no idea wat the triangle stands for :'(
sirm3d
  • sirm3d
\[\left( \frac{ 1 }{ n } \right)^9+...+\left( \frac{ n }{ n } \right)^9=\sum_{i=1}^{n}\left( \frac{ i }{ n } \right)^n\]
anonymous
  • anonymous
i think the way ur doing it is correct... ur using the rem. sum right?
sirm3d
  • sirm3d
\[\large \sum_{i=1}^{n}\left( \frac{ i }{ n } \right)^9=\sum_{i=1}^{n}\left( 0+i\frac{ 1 }{ n } \right)^9\]so a = 0, b=1 (delta x) = 1/n
anonymous
  • anonymous
lol ,,,,
sirm3d
  • sirm3d
therefore \[\large f(x)=x^9\]\ YES, the problem is a riemann sum.
anonymous
  • anonymous
so how did u get 1/10???
anonymous
  • anonymous
got it
anonymous
  • anonymous
ur my hero !!!!
sirm3d
  • sirm3d
^^
anonymous
  • anonymous
can u help me with next one when i close LOL i got an answer. but idk if i got it right...pretty plzzz
sirm3d
  • sirm3d
i'll try. pls post.

Looking for something else?

Not the answer you are looking for? Search for more explanations.