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UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
im not very pleased with the final form of my answer,
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
mabye this is better \[F(p)=\frac{2}{(1e^{4p})p^2}\frac{2e^{2p}}{(1e^{4p})p^2}\frac{4e^{2p}}{(1e^{4p})p}\]
 one year ago

lonliness Group TitleBest ResponseYou've already chosen the best response.0
yes this one is better but the one that you have solved is much better and simplified , so i dont think you need to do this
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
@lonliness , what region should i integrate for figure 2
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
also how did go in this one
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
dw:1354803234598:dw
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
dw:1354803478460:dw
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
dw:1354803608097:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
but if i go from 0 to 2 pi ( in fig2) the the integral will be messy
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
dw:1354804514349:dw
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
dw:1354804529087:dw
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
dw:1354804592320:dw
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
yes! your answer isn't correct because you had some mistake to solving integrals.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
i see that now,
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
Do you know how I understood my mistake? Because I knew that the bounded signals should have Laplace with bounded limit in s=p=0
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
dw:1354805030916:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1354861124769:dw
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.3
dw:1354861368611:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
the slope is 1 and then 1
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
dw:1354862069169:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
@mahmit2012
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
@TuringTest
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
@mahmit2012 s=ROC(region of convergence)+jw(frequency responce) so where the ROC of this function?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
im not sure , i havent herd that term before, is it a restriction on p?
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
actually we moved from fourier transform to laplace transform because fourier transform tells only frequency responce of a signal/function but laplace transform can explain stability/unstability of function including with its frequency responce so its easy to design system by using laplace transform
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
dw:1354866466108:dw
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
\[F(s)=\int\limits_{\infty}^{\infty}f(t)e^st*dt\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[\delta=\sigma\]?
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus am i explain it more if u want?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
yes please
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
oh yes \[s=\sigma+jw\] actually i have not seen it on table before
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
for some reason my text book has been using \(p\) for \(s\) \(x\) for \(t\) \(n\) fr \(\omega\) \(i\) for \(j\)
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
so for moving function(signal) dw:1354867100786:dw now for left sided signal dw:1354867294896:dw dw:1354867371794:dw
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
i am using book of ALAN.V.OPPENHEIM and also book of SAMARJIT.GHOSH
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
Have u know before why we use laplace transform?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
do we use laplace transform to understand the frequencies of the system?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
(also to solve Initial value problems )
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
yes we use laplace transform to find both frequency responce(jw) as well as its stabality and unstabaliy(sigma) of function s=sigma+jw as see above yes also for initial value problem+modulation problem+final value problem i can give u simple function matlab code if u want!!
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
yes i would be interested to try out your matlab code , also what is a modulation problem ?
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
modulation theorem!!!! application of signal and system in communication it is a technique that is use to convey the info over a long distance i.e for voice signal as voice signal dont have high range for long distance actual signal+carrier signal 3400hz+high freq signal(1 Mhz) voice data may die over a long distance if we not use carrier signal signal send for long distance through amplitude modulation as well as frequency modulation we can fix the band width of AM,short band width require if we want to send signal over a lond distance for FM,long band width is needed if we want to send signal for long distance but here there is some cost problem!!i will discuss if u want
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
but frequency modulation is best as noise signals in atmosphere donot affect on it like mobile phone signals we use frequency modulation technique!!! but still its so costly to use Freq modulation
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
ok, can you tell me more about the region of convergence for my triangles signal
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
i ask it for mohan gholami(@mahmit2012)!! he will tell u!!i think he know it!!!
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
btw fren which book u use for signals and systems can u tell me its authur name?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[ \begin{align*} \mathcal L\big\{f(x)\big\}&=\int\limits_0^\infty f(x)e^{px}\cdot\text dx\\ &=\tfrac1{1e^{4p}}\int\limits_0^{4}f(x)e^{px}\cdot\text dx\\ &=\tfrac1{1e^{4p}}\left[\int\limits_0^{2}xe^{px}\cdot\text dx+\int\limits_2^4(4x)e^{px}\cdot\text dx\right]\\ &=\tfrac1{1e^{4p}}\left[\frac{xe^{px}}{p}\Big_0^2\int\limits_0^{2}\frac{e^{px}}{p}\cdot\text dx+4\int\limits_2^4e^{px}\cdot\text dx\int\limits_2^4xe^{px}\cdot\text dx\right]\\ &=\tfrac1{1e^{4p}}\left[\frac{2e^{2p}}{p}\frac{e^{px}}{p^2}\Big_0^2+\frac{4e^{px}}{p}\Big_2^4\frac{xe^{px}}{p}\Big_2^4+\int\limits_2^{4}\frac{e^{px}}{p}\cdot\text dx\right]\\ &=\tfrac1{1e^{4p}}\left[\frac{2e^{2p}}{p}\frac{e^{2p}1}{p^2}+\frac{4e^{4p}4e^{2p}}{p}\tfrac{4e^{4p}2e^{2p}}{p}+\frac{e^{px}}{p^2}\Big_2^4\right]\\ &=\tfrac1{1e^{4p}}\left[\frac{2e^{2p}}{p}+\frac{1e^{2p}}{p^2}+\frac{2e^{2p}}{p}+\frac{e^{4p}e^{2p}}{p^2}\right]\\ &=\frac1{1e^{4p}}\left[\frac{12e^{2p}+4e^{4p}}{p^2}\right]\\ &=\frac{12e^{2p}+4e^{4p}}{(1e^{4p})p^2}\\ \end{align*}\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
is this right for the wave of triangles?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
is there some way to check?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
@sirm3d
 one year ago
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