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Asylum15

  • 3 years ago

Q. Differentiate....

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  1. Asylum15
    • 3 years ago
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    4sin(3x^2+5)ln(2x)

  2. galanh
    • 3 years ago
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    \[d(4uv)/dx =4(udv/dx+vdv/dx) \]

  3. Asylum15
    • 3 years ago
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    Product rule? 4 [Sin(3x^2+5)] [ln(2x)] Sin(3x^2+5 = U Ln(2x) = V?

  4. galanh
    • 3 years ago
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    yes

  5. lopus
    • 3 years ago
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    |dw:1354806153196:dw|

  6. galanh
    • 3 years ago
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    \[dv/dx=\cos (3x ^{2}+5)6x\]

  7. Asylum15
    • 3 years ago
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    Thanks guys :)

  8. galanh
    • 3 years ago
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    \[du/dx=?\]

  9. Asylum15
    • 3 years ago
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    Lopus, you still here?

  10. Asylum15
    • 3 years ago
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    Where does 6x come from?

  11. galanh
    • 3 years ago
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    from the derivative of argument function of sin d(3x**2+5)/dx

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