Asylum15
Q. Differentiate....



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Asylum15
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4sin(3x^2+5)ln(2x)

galanh
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\[d(4uv)/dx =4(udv/dx+vdv/dx) \]

Asylum15
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Product rule?
4 [Sin(3x^2+5)] [ln(2x)]
Sin(3x^2+5 = U
Ln(2x) = V?

galanh
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yes

lopus
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dw:1354806153196:dw

galanh
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\[dv/dx=\cos (3x ^{2}+5)6x\]

Asylum15
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Thanks guys :)

galanh
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\[du/dx=?\]

Asylum15
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Lopus, you still here?

Asylum15
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Where does 6x come from?

galanh
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from the derivative of argument function of sin
d(3x**2+5)/dx