## ForeverRebel 2 years ago Factor completely 5w^3-20w^2+3w-12

1. joshi

you could try factor by grouping which means you would factor 5w^3 and -20w^2 together. and 3w and -12 together

2. ForeverRebel

so it would be...-12w-12?? o my im lost

3. joshi

well lets take 5w^3 -20w^2 for now. what do the numbers 5 and 20 have in common? like you have to see if they can both be 'factored' by the same number.

4. ForeverRebel

5*4=20

5. joshi

yeah that's right! so we can 'take out 5 in common' or factor the 5. basically factoring is just a simpler way of writing the same equation. so 5w^3 -20w^2 = 5(w^3 - 4w^2)

6. joshi

because brackets mean multiplication right? so if you multiplied the 5 you would get the same thing

7. mathstudent55

Factor by grouping. See what you can factor out of the first two terms, and see what you can factor out of the last two terms. 5w^3 - 20w^2 + 3w - 12 first two terms have 5w^2 as common factor last two terms have factor of 3 5w^2(w - 4) + 3(w - 4) Now notice that (w - 4) is a common factor, so take it out (w - 4)(5w^2 + 3)

8. ForeverRebel

9. ForeverRebel

@mathstudent55

10. mathstudent55

Yes, w - 4 cannot be factored, and 5w^2 + 3 cannot be factored, so that's it.