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ForeverRebel
 3 years ago
Factor completely
5w^320w^2+3w12
ForeverRebel
 3 years ago
Factor completely 5w^320w^2+3w12

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joshi
 3 years ago
Best ResponseYou've already chosen the best response.0you could try factor by grouping which means you would factor 5w^3 and 20w^2 together. and 3w and 12 together

ForeverRebel
 3 years ago
Best ResponseYou've already chosen the best response.0so it would be...12w12?? o my im lost

joshi
 3 years ago
Best ResponseYou've already chosen the best response.0well lets take 5w^3 20w^2 for now. what do the numbers 5 and 20 have in common? like you have to see if they can both be 'factored' by the same number.

joshi
 3 years ago
Best ResponseYou've already chosen the best response.0yeah that's right! so we can 'take out 5 in common' or factor the 5. basically factoring is just a simpler way of writing the same equation. so 5w^3 20w^2 = 5(w^3  4w^2)

joshi
 3 years ago
Best ResponseYou've already chosen the best response.0because brackets mean multiplication right? so if you multiplied the 5 you would get the same thing

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1Factor by grouping. See what you can factor out of the first two terms, and see what you can factor out of the last two terms. 5w^3  20w^2 + 3w  12 first two terms have 5w^2 as common factor last two terms have factor of 3 5w^2(w  4) + 3(w  4) Now notice that (w  4) is a common factor, so take it out (w  4)(5w^2 + 3)

ForeverRebel
 3 years ago
Best ResponseYou've already chosen the best response.0is that the answer?

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1Yes, w  4 cannot be factored, and 5w^2 + 3 cannot be factored, so that's it.
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