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ForeverRebel

Factor completely 5w^3-20w^2+3w-12

  • one year ago
  • one year ago

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  1. joshi
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    you could try factor by grouping which means you would factor 5w^3 and -20w^2 together. and 3w and -12 together

    • one year ago
  2. ForeverRebel
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    so it would be...-12w-12?? o my im lost

    • one year ago
  3. joshi
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    well lets take 5w^3 -20w^2 for now. what do the numbers 5 and 20 have in common? like you have to see if they can both be 'factored' by the same number.

    • one year ago
  4. ForeverRebel
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    5*4=20

    • one year ago
  5. joshi
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    yeah that's right! so we can 'take out 5 in common' or factor the 5. basically factoring is just a simpler way of writing the same equation. so 5w^3 -20w^2 = 5(w^3 - 4w^2)

    • one year ago
  6. joshi
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    because brackets mean multiplication right? so if you multiplied the 5 you would get the same thing

    • one year ago
  7. mathstudent55
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    Factor by grouping. See what you can factor out of the first two terms, and see what you can factor out of the last two terms. 5w^3 - 20w^2 + 3w - 12 first two terms have 5w^2 as common factor last two terms have factor of 3 5w^2(w - 4) + 3(w - 4) Now notice that (w - 4) is a common factor, so take it out (w - 4)(5w^2 + 3)

    • one year ago
  8. ForeverRebel
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    is that the answer?

    • one year ago
  9. ForeverRebel
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    @mathstudent55

    • one year ago
  10. mathstudent55
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    Yes, w - 4 cannot be factored, and 5w^2 + 3 cannot be factored, so that's it.

    • one year ago
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