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ethompsonn
Group Title
Solve (x + 2 < 5) ∩ (x  7 > 6).
{x  1 < x < 3}
{x  x < 3 or x > 1}
{all real numbers}
 one year ago
 one year ago
ethompsonn Group Title
Solve (x + 2 < 5) ∩ (x  7 > 6). {x  1 < x < 3} {x  x < 3 or x > 1} {all real numbers}
 one year ago
 one year ago

This Question is Closed

Umangiasd Group TitleBest ResponseYou've already chosen the best response.1
it's not x<3 or x>1 but x<3 AND x>1 (First answer) why? the intersection means that you use "the repeated" data. So it will be (x+2<5=>x<3) (x7>6=>x>1) > so its x ∈ (1,3) (The interval is open in both extremes)
 one year ago
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